| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.54 |
| Score | 0% | 51% |
The principle of conservation of mechanical energy states that, as long as no other forces are applied, what will remain constant as an object falls?
total mechanical energy |
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acceleration |
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kinetic energy |
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potential energy |
As an object falls, its potential energy is converted into kinetic energy. The principle of conservation of mechanical energy states that, as long as no other forces are applied, total mechanical energy (PE + KE) of the object will remain constant at all points in its descent.
| 2.8 | |
| 0.8 | |
| 0.72 | |
| 8.8 |
Mechanical advantage (MA) is the ratio by which effort force relates to resistance force. If both forces are known, calculating MA is simply a matter of dividing resistance force by effort force:
MA = \( \frac{F_r}{F_e} \) = \( \frac{7 ft.}{8.75 ft.} \) = 0.8
In this case, the mechanical advantage is less than one meaning that each unit of effort force results in just 0.8 units of resistance force. However, a third class lever like this isn't designed to multiply force like a first class lever. A third class lever is designed to multiply distance and speed at the resistance by sacrificing force at the resistance. Different lever styles have different purposes and multiply forces in different ways.
Force of friction due to kinetic friction is __________ the force of friction due to static friction.
the same as |
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opposite |
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lower than |
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higher than |
The formula for force of friction (Ff) is the same whether kinetic or static friction applies: Ff = μFN. To distinguish between kinetic and static friction, μk and μs are often used in place of μ.
| 225 ft. | |
| 1.2 ft. | |
| 2.4 ft. | |
| 7.2 ft. |
To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.Solving for da, our missing value, and plugging in our variables yields:
da = \( \frac{R_bd_b}{R_a} \) = \( \frac{60 lbs. \times 3 ft.}{75 lbs.} \) = \( \frac{180 ft⋅lb}{75 lbs.} \) = 2.4 ft.
| 200% | |
| 50% | |
| 25% | |
| 100% |