ASVAB Mechanical Comprehension Practice Test 364105 Results

Your Results Global Average
Questions 5 5
Correct 0 2.93
Score 0% 59%

Review

1

A fixed pulley is useful for which of the following?

53% Answer Correctly

changing the direction of the input force

multiplying the input distance

changing the direction of the output force

multiplying the input force


Solution

A fixed pulley is used to change the direction of a force and does not multiply the force applied. As such, it has a mechanical advantage of one. The benefit of a fixed pulley is that it can allow the force to be applied at a more convenient angle, for example, pulling downward or horizontally to lift an object instead of upward.


2

Which class of lever offers no mechanical advantage?

45% Answer Correctly

none of these, all levers offer mechanical advantage

second

third

first


Solution

A third-class lever is used to increase distance traveled by an object in the same direction as the force applied. The fulcrum is at one end of the lever, the object at the other, and the force is applied between them. This lever does not impart a mechanical advantage as the effort force must be greater than the load but does impart extra speed to the load. Examples of third-class levers are shovels and tweezers.


3 What's the mechanical advantage of a wedge that's 5 inches wide and 30 inches long?
83% Answer Correctly
5.4
8
3
6

Solution

The mechanical advantage (MA) of a wedge is its length divided by its thickness:

MA = \( \frac{l}{t} \) = \( \frac{30 in.}{5 in.} \) = 6


4 The green box weighs 75 lbs. and a 30 lbs. weight is placed 3 ft. from the fulcrum at the blue arrow. How far from the fulcrum would the green box need to be placed to balance the lever?
57% Answer Correctly
25 ft.
0.4 ft.
1.2 ft.
3.6 ft.

Solution

To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.

Solving for da, our missing value, and plugging in our variables yields:

da = \( \frac{R_bd_b}{R_a} \) = \( \frac{30 lbs. \times 3 ft.}{75 lbs.} \) = \( \frac{90 ft⋅lb}{75 lbs.} \) = 1.2 ft.


5

Boyle's law defines the relationship between pressure and volume as:

57% Answer Correctly

\({P_1}{P_2} = {V_1}{V_2}\)

\(\frac{P_1}{P_2} = \frac{V_2}{V_1}\)

\(\frac{P_1}{P_2} = \frac{V_1}{V_2}\)

\(\frac{P_1}{P_2} = {V_1}{V_2}\)


Solution

Boyle's law states that "for a fixed amount of an ideal gas kept at a fixed temperature, pressure and volume are inversely proportional". Expressed as a formula, that's \(\frac{P_1}{P_2} = \frac{V_2}{V_1}\)