ASVAB Mechanical Comprehension Practice Test 386759 Results

Your Results Global Average
Questions 5 5
Correct 0 3.16
Score 0% 63%

Review

1

Coplanar forces:

61% Answer Correctly

act in a common plane

pass through a common point

have opposite dimensions

act along the same line of action


Solution

Collinear forces act along the same line of action, concurrent forces pass through a common point and coplanar forces act in a common plane.


2 If the green arrow in this diagram represents 680 ft⋅lb of work, how far will the box move if it weighs 170 pounds?
72% Answer Correctly
4 ft.
85 ft.
0 ft.
2 ft.

Solution
The Law of Work states that the work put into a machine is equal to the work received from the machine under ideal conditions. In equation form, that's:

Win = Wout
Feffort x deffort = Fresistance x dresistance

In this problem, the effort work is 680 ft⋅lb and the resistance force is 170 lbs. and we need to calculate the resistance distance:

Win = Fresistance x dresistance
680 ft⋅lb = 170 lbs. x dresistance
dresistance = \( \frac{680ft⋅lb}{170 lbs.} \) = 4 ft.


3

The force exerted on an object due to gravity is called:

70% Answer Correctly

mass

density

potential energy

weight


Solution

Mass is an intrinsic property of matter and does not vary. Weight is the force exerted on the mass of an object due to gravity and a specific case of Newton's Second Law of Motion. Replace force with weight and acceleration with acceleration due to gravity on Earth (g) and the result is the formula for weight: W = mg or, substituting for g, weight equals mass multiplied by 9.8 m/s2.


4

Which of the following will increase the mechanical advantage of a second-class lever?

55% Answer Correctly

decrease the length of the lever

move the object being lifted closer to the fulcrum

move the fulcrum between the force and the object being lifted

move the object being lifted farther away from the fulcrum


Solution

A second-class lever is used to increase force on an object in the same direction as the force is applied. This lever requires a smaller force to lift a larger load but the force must be applied over a greater distance. The fulcrum is placed at one end of the lever and mechanical advantage increases as the object being lifted is moved closer to the fulcrum or the length of the lever is increased. An example of a second-class lever is a wheelbarrow.


5

Boyle's law defines the relationship between pressure and volume as:

57% Answer Correctly

\(\frac{P_1}{P_2} = \frac{V_1}{V_2}\)

\({P_1}{P_2} = {V_1}{V_2}\)

\(\frac{P_1}{P_2} = {V_1}{V_2}\)

\(\frac{P_1}{P_2} = \frac{V_2}{V_1}\)


Solution

Boyle's law states that "for a fixed amount of an ideal gas kept at a fixed temperature, pressure and volume are inversely proportional". Expressed as a formula, that's \(\frac{P_1}{P_2} = \frac{V_2}{V_1}\)