ASVAB Mechanical Comprehension Practice Test 387608 Results

Your Results Global Average
Questions 5 5
Correct 0 2.98
Score 0% 60%

Review

1

Which of the following is not a type of structural load?

49% Answer Correctly

live load

occupancy load

dead load

wind load


Solution

Dead load is the weight of the building and materials, live load is additional weight due to occupancy or use, snow load is the weight of accumulated snow on a structure and wind load is the force of wind pressures against structure surfaces.


2

For any given surface, the coefficient of static friction is ___________ the coefficient of kinetic friction.

54% Answer Correctly

equal to

opposite

higher than

lower than


Solution

For any given surface, the coefficient of static friction is higher than the coefficient of kinetic friction. More force is required to initally get an object moving than is required to keep it moving. Additionally, static friction only arises in response to an attempt to move an object (overcome the normal force between it and the surface).


3

A block and tackle with four pulleys would have a mechanical advantage of:

79% Answer Correctly

4

2

1

0


Solution

Two or more pulleys used together constitute a block and tackle which, unlike a fixed pulley, does impart mechanical advantage as a function of the number of pulleys that make up the arrangement.  So, for example, a block and tackle with three pulleys would have a mechanical advantage of three.


4 If a 50 lbs. weight is placed 7 ft. from the fulcrum at the blue arrow and the green box is 4 ft. from the fulcrum, how much would the green box have to weigh to balance the lever?
61% Answer Correctly
0 lbs.
350 lbs.
21.88 lbs.
87.5 lbs.

Solution

To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.

Solving for Ra, our missing value, and plugging in our variables yields:

Ra = \( \frac{R_bd_b}{d_a} \) = \( \frac{50 lbs. \times 7 ft.}{4 ft.} \) = \( \frac{350 ft⋅lb}{4 ft.} \) = 87.5 lbs.


5 If the green box weighs 25 lbs. and 25 lbs. of force is applied 3 ft. from the fulcrum at the blue arrow, how far from the fulcrum would the green box need to be placed to balance the lever?
55% Answer Correctly
3 ft.
1.5 ft.
6 ft.
12 ft.

Solution

To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.

Solving for da, our missing value, and plugging in our variables yields:

da = \( \frac{R_bd_b}{R_a} \) = \( \frac{25 lbs. \times 3 ft.}{25 lbs.} \) = \( \frac{75 ft⋅lb}{25 lbs.} \) = 3 ft.