| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.02 |
| Score | 0% | 60% |
Depending on where you apply effort and resistance, the wheel and axle can multiply:
force or distance |
|
speed or power |
|
power or distance |
|
force or speed |
If you apply the resistance to the axle and the effort to the wheel, the wheel and axle will multiply force and if you apply the resistance to the wheel and the effort to the axle, it will multiply speed.
| 12000ft⋅lb | |
| 3000 ft⋅lb | |
| 6000ft⋅lb | |
| 750ft⋅lb |
Two gears are connected and the smaller gear drives the larger gear. The speed of rotation will __________ and the torque will __________.
decrease, decrease |
|
increase, decrease |
|
decrease, increase |
|
increase, increase |
Connected gears of different numbers of teeth are used together to change the rotational speed and torque of the input force. If the smaller gear drives the larger gear, the speed of rotation will be reduced and the torque will increase. If the larger gear drives the smaller gear, the speed of rotation will increase and the torque will be reduced.
What type of load creates different stresses at different locations on a structure?
impact load |
|
dynamic load |
|
non-uniformly distributed load |
|
static uniformly distributed load |
A concentrated load acts on a relatively small area of a structure, a static uniformly distributed load doesn't create specific stress points or vary with time, a dynamic load varies with time or affects a structure that experiences a high degree of movement, an impact load is sudden and for a relatively short duration and a non-uniformly distributed load creates different stresses at different locations on a structure.
| 0.25 ft. | |
| 0 ft. | |
| 0.06 ft. | |
| 0.08 ft. |
To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.Solving for db, our missing value, and plugging in our variables yields:
db = \( \frac{R_ad_a}{R_b} \) = \( \frac{5 lbs. \times 1 ft.}{20 lbs.} \) = \( \frac{5 ft⋅lb}{20 lbs.} \) = 0.25 ft.