| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.03 |
| Score | 0% | 61% |
| 12 | |
| 3 | |
| 3.3 | |
| 4.5 |
The mechanical advantage (MA) of a wedge is its length divided by its thickness:
MA = \( \frac{l}{t} \) = \( \frac{6 in.}{2 in.} \) = 3
The principle of moments defines equilibrium in terms of:
energy |
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torque |
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power |
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speed |
According to the principle of moments, you can maintain equilibrium if the moments (forces) tending to clockwise rotation are equal to the moments tending to counterclockwise rotation. Another name for these moments of force is torque.
Assuming force applied remains constant, which of the following will result in more work being done?
moving the object with more speed |
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moving the object farther |
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moving the object with more acceleration |
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increasing the coefficient of friction |
Work is accomplished when force is applied to an object: W = Fd where F is force in newtons (N) and d is distance in meters (m). Thus, the more force that must be applied to move an object, the more work is done and the farther an object is moved by exerting force, the more work is done.
For any given surface, the coefficient of static friction is ___________ the coefficient of kinetic friction.
equal to |
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opposite |
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lower than |
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higher than |
For any given surface, the coefficient of static friction is higher than the coefficient of kinetic friction. More force is required to initally get an object moving than is required to keep it moving. Additionally, static friction only arises in response to an attempt to move an object (overcome the normal force between it and the surface).
| 77.14 lbs. | |
| 38.57 lbs. | |
| 0 lbs. | |
| 115.71 lbs. |
To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.Solving for Ra, our missing value, and plugging in our variables yields:
Ra = \( \frac{R_bd_b}{d_a} \) = \( \frac{30 lbs. \times 9 ft.}{7 ft.} \) = \( \frac{270 ft⋅lb}{7 ft.} \) = 38.57 lbs.