| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.42 |
| Score | 0% | 68% |
For any given surface, the coefficient of static friction is ___________ the coefficient of kinetic friction.
equal to |
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lower than |
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opposite |
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higher than |
For any given surface, the coefficient of static friction is higher than the coefficient of kinetic friction. More force is required to initally get an object moving than is required to keep it moving. Additionally, static friction only arises in response to an attempt to move an object (overcome the normal force between it and the surface).
Potential energy is energy that has the potential to be converted into what?
work |
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power |
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heat |
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kinetic energy |
Potential energy is the energy of an object by virtue of its position relative to other objects. It is energy that has the potential to be converted into kinetic energy.
What type of load acts on a relatively small area of a structure?
non-uniformly distributed load |
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impact load |
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concentrated load |
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dynamic load |
A concentrated load acts on a relatively small area of a structure, a static uniformly distributed load doesn't create specific stress points or vary with time, a dynamic load varies with time or affects a structure that experiences a high degree of movement, an impact load is sudden and for a relatively short duration and a non-uniformly distributed load creates different stresses at different locations on a structure.
Which of the following surfaces would have the highest coefficient of friction?
steel |
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concrete |
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ice |
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marble |
Coefficient of friction (μ) represents how much two materials resist sliding across each other. Smooth surfaces like ice have low coefficients of friction while rough surfaces like concrete have high μ.
| 1.67 ft. | |
| 12 ft. | |
| 0 ft. | |
| 0.42 ft. |
To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.Solving for da, our missing value, and plugging in our variables yields:
da = \( \frac{R_bd_b}{R_a} \) = \( \frac{5 lbs. \times 5 ft.}{60 lbs.} \) = \( \frac{25 ft⋅lb}{60 lbs.} \) = 0.42 ft.