ASVAB Mechanical Comprehension Practice Test 406012 Results

Your Results Global Average
Questions 5 5
Correct 0 3.42
Score 0% 68%

Review

1

For any given surface, the coefficient of static friction is ___________ the coefficient of kinetic friction.

54% Answer Correctly

equal to

lower than

opposite

higher than


Solution

For any given surface, the coefficient of static friction is higher than the coefficient of kinetic friction. More force is required to initally get an object moving than is required to keep it moving. Additionally, static friction only arises in response to an attempt to move an object (overcome the normal force between it and the surface).


2

Potential energy is energy that has the potential to be converted into what?

81% Answer Correctly

work

power

heat

 kinetic energy


Solution

Potential energy is the energy of an object by virtue of its position relative to other objects. It is energy that has the potential to be converted into kinetic energy.


3

What type of load acts on a relatively small area of a structure?

74% Answer Correctly

non-uniformly distributed load

impact load

concentrated load

dynamic load


Solution

A concentrated load acts on a relatively small area of a structure, a static uniformly distributed load doesn't create specific stress points or vary with time, a dynamic load varies with time or affects a structure that experiences a high degree of movement, an impact load is sudden and for a relatively short duration and a non-uniformly distributed load creates different stresses at different locations on a structure.


4

Which of the following surfaces would have the highest coefficient of friction?

77% Answer Correctly

steel

concrete

ice

marble


Solution

Coefficient of friction (μ) represents how much two materials resist sliding across each other.  Smooth surfaces like ice have low coefficients of friction while rough surfaces like concrete have high μ.


5 If the green box weighs 60 lbs. and 5 lbs. of force is applied 5 ft. from the fulcrum at the blue arrow, how far from the fulcrum would the green box need to be placed to balance the lever?
55% Answer Correctly
1.67 ft.
12 ft.
0 ft.
0.42 ft.

Solution

To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.

Solving for da, our missing value, and plugging in our variables yields:

da = \( \frac{R_bd_b}{R_a} \) = \( \frac{5 lbs. \times 5 ft.}{60 lbs.} \) = \( \frac{25 ft⋅lb}{60 lbs.} \) = 0.42 ft.