| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.51 |
| Score | 0% | 70% |
| 42 lbs. | |
| 168 lbs. | |
| 84 lbs. | |
| 126 lbs. |
To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.Solving for Ra, our missing value, and plugging in our variables yields:
Ra = \( \frac{R_bd_b}{d_a} \) = \( \frac{35 lbs. \times 6 ft.}{5 ft.} \) = \( \frac{210 ft⋅lb}{5 ft.} \) = 42 lbs.
The standard unit of energy is the:
Horsepower |
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Joule |
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Volt |
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Watt |
The Joule (J) is the standard unit of energy and has the unit \({kg \times m^2} \over s^2\).
Tension is a force that does which of the following?
slows an object |
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stretches an object |
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heats up an object |
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compacts an object |
Tension is a force that stretches or elongates something. When a cable or rope is used to pull an object, for example, it stretches internally as it accepts the weight that it's moving. Although tension is often treated as applying equally to all parts of a material, it's greater at the places where the material is under the most stress.
| 5 | |
| 8 | |
| 1 | |
| 9 |
The gear ratio (Vr) of a gear train is the product of the gear ratios between the pairs of meshed gears. Let N represent the number of teeth for each gear:
Vr = \( \frac{N_1}{N_2} \) \( \frac{N_2}{N_3} \) \( \frac{N_3}{N_4} \) ... \( \frac{N_n}{N_{n+1}} \)
In this problem, we have only two gears so the equation becomes:Vr = \( \frac{N_1}{N_2} \) = \( \frac{40}{8} \) = 5
Sam can do 50 ft. lb. of work in 2 minutes and 5 seconds. What would Sam have to do to increase his power output?
do 100 ft. lb. of work in 4 minutes 12 seconds |
|
do 25 ft. lb. of work in 2 minutes 5 seconds |
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do the work in 3 minutes |
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do the work in 2 minutes |
Power is the rate of doing work or \(\frac{W}{t}\). To increase power, increase the work being done in the same amount of time or do the same amount of work in less time.