ASVAB Mechanical Comprehension Practice Test 412604 Results

Your Results Global Average
Questions 5 5
Correct 0 2.83
Score 0% 57%

Review

1 If 15 lbs. of force is applied 9 ft. from the fulcrum at the blue arrow and the green box is 8 ft. from the fulcrum, how much would the green box have to weigh to balance the lever?
62% Answer Correctly
67.5 lbs.
4.22 lbs.
16.88 lbs.
50.63 lbs.

Solution

To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.

Solving for Ra, our missing value, and plugging in our variables yields:

Ra = \( \frac{R_bd_b}{d_a} \) = \( \frac{15 lbs. \times 9 ft.}{8 ft.} \) = \( \frac{135 ft⋅lb}{8 ft.} \) = 16.88 lbs.


2 If this lever is in equilibrium with an effort force of 7.14 ft. lb. at the blue arrow and a resistance force of 5 ft. lb. at the green box, what is its mechanical advantage?
48% Answer Correctly
2.1
0.7
7.7
3.7

Solution

Mechanical advantage (MA) is the ratio by which effort force relates to resistance force. If both forces are known, calculating MA is simply a matter of dividing resistance force by effort force:

MA = \( \frac{F_r}{F_e} \) = \( \frac{5 ft.}{7.14 ft.} \) = 0.7

In this case, the mechanical advantage is less than one meaning that each unit of effort force results in just 0.7 units of resistance force. However, a third class lever like this isn't designed to multiply force like a first class lever. A third class lever is designed to multiply distance and speed at the resistance by sacrificing force at the resistance. Different lever styles have different purposes and multiply forces in different ways.


3

Boyle's law defines the relationship between pressure and volume as:

57% Answer Correctly

\(\frac{P_1}{P_2} = {V_1}{V_2}\)

\({P_1}{P_2} = {V_1}{V_2}\)

\(\frac{P_1}{P_2} = \frac{V_2}{V_1}\)

\(\frac{P_1}{P_2} = \frac{V_1}{V_2}\)


Solution

Boyle's law states that "for a fixed amount of an ideal gas kept at a fixed temperature, pressure and volume are inversely proportional". Expressed as a formula, that's \(\frac{P_1}{P_2} = \frac{V_2}{V_1}\)


4

Assuming force applied remains constant, which of the following will result in more work being done?

53% Answer Correctly

moving the object farther

moving the object with more speed

increasing the coefficient of friction

moving the object with more acceleration


Solution

Work is accomplished when force is applied to an object: W = Fd where F is force in newtons (N) and d is distance in meters (m). Thus, the more force that must be applied to move an object, the more work is done and the farther an object is moved by exerting force, the more work is done.


5

What is the first step to solving a problem where multiple forces are acting on an object?

61% Answer Correctly

calculate the total force

calculate kinetic energy

calculate potential energy

calculate the net force


Solution

In mechanics, multiple forces are often acting on a particular object and, taken together, produce the net force acting on that object. Like force, net force is a vector quantity in that it has magnitude and direction.