| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.22 |
| Score | 0% | 64% |
When it comes to force, mass and acceleration have what kind of relationship?
exponential |
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linear |
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inverse |
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logarithmic |
Newton's Second Law of Motion states that "The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object." This Law describes the linear relationship between mass and acceleration when it comes to force and leads to the formula F = ma or force equals mass multiplied by rate of acceleration.
| 1.67 lbs. | |
| 3.33 lbs. | |
| 0.56 lbs. | |
| 5 lbs. |
To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.Solving for Rb, our missing value, and plugging in our variables yields:
Rb = \( \frac{R_ad_a}{d_b} \) = \( \frac{5 lbs. \times 2 ft.}{6 ft.} \) = \( \frac{10 ft⋅lb}{6 ft.} \) = 1.67 lbs.
A wedge is most similar to what other type of simple machine?
third-class lever |
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first-class lever |
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second-class lever |
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inclined plane |
The wedge is a moving inclined plane that is used to lift, hold, or break apart an object. A wedge converts force applied to its blunt end into force perpendicular to its inclined surface. In contrast to a stationary plane where force is applied to the object being moved, with a wedge the object is stationary and the force is being applied to the plane. Examples of a wedge include knives and chisels.
A box is resting on a smooth floor. Static friction is present:
at all times |
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only if normal force is present |
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if the coefficient of friction is greater than one |
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when an attempt is made to move the box |
For any given surface, the coefficient of static friction is higher than the coefficient of kinetic friction. More force is required to initally get an object moving than is required to keep it moving. Additionally, static friction only arises in response to an attempt to move an object (overcome the normal force between it and the surface).
| 280 ft. | |
| 1.75 ft. | |
| 5 ft. | |
| 1 ft. |
fAdA = fBdB
For this problem, the equation becomes:
10 lbs. x 7 ft. = 40 lbs. x dB
dB = \( \frac{10 \times 7 ft⋅lb}{40 lbs.} \) = \( \frac{70 ft⋅lb}{40 lbs.} \) = 1.75 ft.