ASVAB Mechanical Comprehension Practice Test 449769 Results

Your Results Global Average
Questions 5 5
Correct 0 2.92
Score 0% 58%

Review

1 If the radius of the axle is 7 and the radius of the wheel is 8, what is the mechanical advantage of this wheel and axle configuration?
41% Answer Correctly
1
0.88
8
1.14

Solution

The mechanical advantage of a wheel and axle is the input radius divided by the output radius:

MA = \( \frac{r_i}{r_o} \)

In this case, the input radius (where the effort force is being applied) is 7 and the output radius (where the resistance is being applied) is 8 for a mechanical advantage of \( \frac{7}{8} \) = 0.88


2

One Horsepower (hp) is equal to how many watts?

76% Answer Correctly

1

746

9.8

1492


Solution

Power is the rate at which work is done, P = w/t, or work per unit time. The watt (W) is the unit for power and is equal to 1 joule (or newton-meter) per second. Horsepower (hp) is another familiar unit of power used primarily for rating internal combustion engines. 1 hp equals 746 watts.


3 If the green box weighs 45 lbs. and is 5 ft. from the fulcrum, how far from the fulcrum would a 55 lbs. force need to be applied to balance the lever?
58% Answer Correctly
4.09 ft.
8.18 ft.
12.27 ft.
16.36 ft.

Solution

To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.

Solving for db, our missing value, and plugging in our variables yields:

db = \( \frac{R_ad_a}{R_b} \) = \( \frac{45 lbs. \times 5 ft.}{55 lbs.} \) = \( \frac{225 ft⋅lb}{55 lbs.} \) = 4.09 ft.


4 If the green box weighs 10 lbs. and is 5 ft. from the fulcrum, how far from the fulcrum would a 60 lbs. weight need to be placed to balance the lever?
61% Answer Correctly
3.33 ft.
2.5 ft.
0.28 ft.
0.83 ft.

Solution

To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.

Solving for db, our missing value, and plugging in our variables yields:

db = \( \frac{R_ad_a}{R_b} \) = \( \frac{10 lbs. \times 5 ft.}{60 lbs.} \) = \( \frac{50 ft⋅lb}{60 lbs.} \) = 0.83 ft.


5

Specific gravity is a comparison of the density of an object with the density of:

57% Answer Correctly

oil

air

carbon

water


Solution

Specific gravity is the ratio of the density of equal volumes of a substance and water and is measured by a hyrdometer.