| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.98 |
| Score | 0% | 60% |
A ramp is an example of which kind of simple machine?
none of these |
|
first-class lever |
|
inclined plane |
|
wedge |
An inclined plane is a simple machine that reduces the force needed to raise an object to a certain height. Work equals force x distance and, by increasing the distance that the object travels, an inclined plane reduces the force necessary to raise it to a particular height. In this case, the mechanical advantage is to make the task easier. An example of an inclined plane is a ramp.
Which of the following is not a type of simple machine?
lever |
|
screw |
|
pulley |
|
gear |
The six types of simple machines are the lever, wheel and axle, pulley, inclined plane, wedge, and screw.
Which of the following statements about this pulley configuration is false?
Mechanical advantage is the number of ropes that support the resistance |
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Changes the direction of and multiplies the effort force |
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Only multiplies the effort force |
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This is a block and tackle pulley configuration |
A block and tackle is a combination of one or more fixed pulleys and one or more movable pulleys where the fixed pulleys change the direction of the effort force and the movable pulleys multiply it. The mechanical advantage is equal to the number of times the effort force changes direction and can be increased by adding more pulley wheels to the system. An easy way to find the mechanical advantage of a block and tackle pulley system is to count the number of ropes that support the resistance.
| 16.5 | |
| 6.1 | |
| 5.5 | |
| 1.8 |
The mechanical advantage of a gear train is its gear ratio. The gear ratio (Vr) is the product of the gear ratios between the pairs of meshed gears. Let N represent the number of teeth for each gear:
Vr = \( \frac{N_1}{N_2} \) \( \frac{N_2}{N_3} \) \( \frac{N_3}{N_4} \) ... \( \frac{N_n}{N_{n+1}} \)
In this problem, we have three gears so the equation becomes:
Vr = \( \frac{N_1}{N_2} \) \( \frac{N_2}{N_3} \) = \( \frac{22}{20} \) \( \frac{20}{4} \) = \( \frac{22}{4} \) = 5.5
| 4.09 ft. | |
| 275 ft. | |
| 16.36 ft. | |
| 11 ft. |
To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.Solving for da, our missing value, and plugging in our variables yields:
da = \( \frac{R_bd_b}{R_a} \) = \( \frac{45 lbs. \times 5 ft.}{55 lbs.} \) = \( \frac{225 ft⋅lb}{55 lbs.} \) = 4.09 ft.