ASVAB Mechanical Comprehension Practice Test 454179 Results

Your Results Global Average
Questions 5 5
Correct 0 2.98
Score 0% 60%

Review

1

A ramp is an example of which kind of simple machine?

84% Answer Correctly

none of these

first-class lever

inclined plane

wedge


Solution

An inclined plane is a simple machine that reduces the force needed to raise an object to a certain height. Work equals force x distance and, by increasing the distance that the object travels, an inclined plane reduces the force necessary to raise it to a particular height. In this case, the mechanical advantage is to make the task easier. An example of an inclined plane is a ramp.


2

Which of the following is not a type of simple machine?

58% Answer Correctly

lever

screw

pulley

gear


Solution

The six types of simple machines are the lever, wheel and axle, pulley, inclined plane, wedge, and screw.


3

Which of the following statements about this pulley configuration is false?

48% Answer Correctly

Mechanical advantage is the number of ropes that support the resistance

Changes the direction of and multiplies the effort force

Only multiplies the effort force

This is a block and tackle pulley configuration


Solution

A block and tackle is a combination of one or more fixed pulleys and one or more movable pulleys where the fixed pulleys change the direction of the effort force and the movable pulleys multiply it. The mechanical advantage is equal to the number of times the effort force changes direction and can be increased by adding more pulley wheels to the system. An easy way to find the mechanical advantage of a block and tackle pulley system is to count the number of ropes that support the resistance.


4 If you have a gear train with three gears, the first with 22 teeth, the second with 20 teeth, and the third with 4 teeth, what is its mechanical advantage?
50% Answer Correctly
16.5
6.1
5.5
1.8

Solution

The mechanical advantage of a gear train is its gear ratio. The gear ratio (Vr) is the product of the gear ratios between the pairs of meshed gears. Let N represent the number of teeth for each gear:

Vr = \( \frac{N_1}{N_2} \) \( \frac{N_2}{N_3} \) \( \frac{N_3}{N_4} \) ... \( \frac{N_n}{N_{n+1}} \)

In this problem, we have three gears so the equation becomes:

Vr = \( \frac{N_1}{N_2} \) \( \frac{N_2}{N_3} \) = \( \frac{22}{20} \) \( \frac{20}{4} \) = \( \frac{22}{4} \) = 5.5


5 The green box weighs 55 lbs. and a 45 lbs. weight is placed 5 ft. from the fulcrum at the blue arrow. How far from the fulcrum would the green box need to be placed to balance the lever?
57% Answer Correctly
4.09 ft.
275 ft.
16.36 ft.
11 ft.

Solution

To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.

Solving for da, our missing value, and plugging in our variables yields:

da = \( \frac{R_bd_b}{R_a} \) = \( \frac{45 lbs. \times 5 ft.}{55 lbs.} \) = \( \frac{225 ft⋅lb}{55 lbs.} \) = 4.09 ft.