ASVAB Mechanical Comprehension Practice Test 454976 Results

Your Results Global Average
Questions 5 5
Correct 0 3.32
Score 0% 66%

Review

1 If the green box weighs 50 lbs. and 55 lbs. of force is applied 9 ft. from the fulcrum at the blue arrow, how far from the fulcrum would the green box need to be placed to balance the lever?
55% Answer Correctly
19.8 ft.
2.48 ft.
9.9 ft.
39.6 ft.

Solution

To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.

Solving for da, our missing value, and plugging in our variables yields:

da = \( \frac{R_bd_b}{R_a} \) = \( \frac{55 lbs. \times 9 ft.}{50 lbs.} \) = \( \frac{495 ft⋅lb}{50 lbs.} \) = 9.9 ft.


2

Which of the following is the formula for torque?

61% Answer Correctly

τ = rF

τ = F/r

τ = r/F

τ = F/r2


Solution

Torque measures force applied during rotation: τ = rF.  Torque (τ, the Greek letter tau) = the radius of the lever arm (r) multiplied by the force (F) applied. Radius is measured from the center of rotation or fulcrum to the point at which the perpendicular force is being applied. The resulting unit for torque is newton-meter (N-m) or foot-pound (ft-lb).


3 If the green box weighs 50 lbs. and is 5 ft. from the fulcrum, how far from the fulcrum would a 15 lbs. force need to be applied to balance the lever?
58% Answer Correctly
0 ft.
50 ft.
16.67 ft.
5.56 ft.

Solution

To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.

Solving for db, our missing value, and plugging in our variables yields:

db = \( \frac{R_ad_a}{R_b} \) = \( \frac{50 lbs. \times 5 ft.}{15 lbs.} \) = \( \frac{250 ft⋅lb}{15 lbs.} \) = 16.67 ft.


4

The force required to initally get an object moving is __________ the force required to keep it moving. 

76% Answer Correctly

the same as

lower than

opposite

higher than


Solution

For any given surface, the coefficient of static friction is higher than the coefficient of kinetic friction. More force is required to initally get an object moving than is required to keep it moving. Additionally, static friction only arises in response to an attempt to move an object (overcome the normal force between it and the surface).


5

Which of these is the formula for force?

77% Answer Correctly

F = am2

F = ma

F = m/a

F = a/m


Solution

Newton's Second Law of Motion states that "The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object." This Law describes the linear relationship between mass and acceleration when it comes to force and leads to the formula F = ma or force equals mass multiplied by rate of acceleration.