| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.88 |
| Score | 0% | 58% |
Boyle's law defines the relationship between pressure and volume as:
\(\frac{P_1}{P_2} = \frac{V_2}{V_1}\) |
|
\(\frac{P_1}{P_2} = {V_1}{V_2}\) |
|
\({P_1}{P_2} = {V_1}{V_2}\) |
|
\(\frac{P_1}{P_2} = \frac{V_1}{V_2}\) |
Boyle's law states that "for a fixed amount of an ideal gas kept at a fixed temperature, pressure and volume are inversely proportional". Expressed as a formula, that's \(\frac{P_1}{P_2} = \frac{V_2}{V_1}\)
The work done by the sum of all forces acting on a particle equals the change in the kinetic energy of the particle. This defines which of the following?
Pascal's law |
|
conservation of mechanical energy |
|
mechanical advantage |
|
work-energy theorem |
The work-energy theorem states that the work done by the sum of all forces acting on a particle equals the change in the kinetic energy of the particle. Simply put, work imparts kinetic energy to the matter upon which the work is being done.
| 55 ft. | |
| 0.73 ft. | |
| 0 ft. | |
| 0.24 ft. |
To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.Solving for db, our missing value, and plugging in our variables yields:
db = \( \frac{R_ad_a}{R_b} \) = \( \frac{55 lbs. \times 1 ft.}{75 lbs.} \) = \( \frac{55 ft⋅lb}{75 lbs.} \) = 0.73 ft.
A fixed pulley has a mechanical advantage of:
0 |
|
-1 |
|
2 |
|
1 |
A fixed pulley is used to change the direction of a force and does not multiply the force applied. As such, it has a mechanical advantage of one. The benefit of a fixed pulley is that it can allow the force to be applied at a more convenient angle, for example, pulling downward or horizontally to lift an object instead of upward.
| 1237.5 \( \frac{ft⋅lb}{s} \) | |
| 2475 \( \frac{ft⋅lb}{s} \) | |
| 3712.5 \( \frac{ft⋅lb}{s} \) | |
| 0 \( \frac{ft⋅lb}{s} \) |