| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.27 |
| Score | 0% | 65% |
| 6.55 ft. | |
| 4 ft. | |
| 0 ft. | |
| 19.64 ft. |
To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.Solving for db, our missing value, and plugging in our variables yields:
db = \( \frac{R_ad_a}{R_b} \) = \( \frac{40 lbs. \times 9 ft.}{55 lbs.} \) = \( \frac{360 ft⋅lb}{55 lbs.} \) = 6.55 ft.
Which of the following is the formula for torque?
τ = r/F |
|
τ = F/r2 |
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τ = F/r |
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τ = rF |
Torque measures force applied during rotation: τ = rF. Torque (τ, the Greek letter tau) = the radius of the lever arm (r) multiplied by the force (F) applied. Radius is measured from the center of rotation or fulcrum to the point at which the perpendicular force is being applied. The resulting unit for torque is newton-meter (N-m) or foot-pound (ft-lb).
Tension is a force that does which of the following?
heats up an object |
|
slows an object |
|
compacts an object |
|
stretches an object |
Tension is a force that stretches or elongates something. When a cable or rope is used to pull an object, for example, it stretches internally as it accepts the weight that it's moving. Although tension is often treated as applying equally to all parts of a material, it's greater at the places where the material is under the most stress.
| 1800 ft⋅lb | |
| 0ft⋅lb | |
| 3600ft⋅lb | |
| 7200ft⋅lb |
| 5 lbs. | |
| 12 lbs. | |
| 35 lbs. | |
| 6 lbs. |
The mechanical advantage of a wheel and axle is the input radius divided by the output radius:
MA = \( \frac{r_i}{r_o} \)
In this case, the input radius (where the effort force is being applied) is 6 and the output radius (where the resistance is being applied) is 3 for a mechanical advantage of \( \frac{6}{3} \) = 2.0
MA = \( \frac{load}{effort} \) so effort = \( \frac{load}{MA} \) = \( \frac{70 lbs.}{2.0} \) = 35 lbs.