| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.32 |
| Score | 0% | 66% |
Specific gravity is a comparison of the density of an object with the density of:
oil |
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carbon |
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water |
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air |
Specific gravity is the ratio of the density of equal volumes of a substance and water and is measured by a hyrdometer.
| 6 | |
| 2 | |
| 15 | |
| 7.5 |
Mechanical advantage is resistance force divided by effort force:
MA = \( \frac{F_r}{F_e} \) = \( \frac{60 lbs.}{10 lbs.} \) = 6
If the handles of a wheelbarrow are 3 ft. from the wheel axle, what force must you exert to lift the handles if it's carrying a 270 lb. load concentrated at a point 0.5 ft. from the axle?
45 lbs |
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810 lbs |
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90 lbs |
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0.83 lbs |
This problem describes a second-class lever and, for a second class lever, the effort force multiplied by the effort distance equals the resistance force multipied by the resistance distance: Fede = Frdr. Plugging in the variables from this problem yields:
Fe x 3 ft. = 270 lbs x 0.5 ft
Fe = 135 ft-lb. / 3 ft
Fe = 45 lbs
| 0 ft. | |
| 0.2 ft. | |
| 0.07 ft. | |
| 0.6 ft. |
To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.Solving for db, our missing value, and plugging in our variables yields:
db = \( \frac{R_ad_a}{R_b} \) = \( \frac{15 lbs. \times 1 ft.}{75 lbs.} \) = \( \frac{15 ft⋅lb}{75 lbs.} \) = 0.2 ft.
The force required to initally get an object moving is __________ the force required to keep it moving.
higher than |
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lower than |
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the same as |
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opposite |
For any given surface, the coefficient of static friction is higher than the coefficient of kinetic friction. More force is required to initally get an object moving than is required to keep it moving. Additionally, static friction only arises in response to an attempt to move an object (overcome the normal force between it and the surface).