| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.14 |
| Score | 0% | 63% |
A box is resting on a smooth floor. Static friction is present:
at all times |
|
if the coefficient of friction is greater than one |
|
only if normal force is present |
|
when an attempt is made to move the box |
For any given surface, the coefficient of static friction is higher than the coefficient of kinetic friction. More force is required to initally get an object moving than is required to keep it moving. Additionally, static friction only arises in response to an attempt to move an object (overcome the normal force between it and the surface).
| 15 ft⋅lb | |
| 540 ft⋅lb | |
| 135 ft⋅lb | |
| 33 ft⋅lb |
| 0 ft. | |
| 5.73 ft. | |
| 17.18 ft. | |
| 11.45 ft. |
To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.Solving for db, our missing value, and plugging in our variables yields:
db = \( \frac{R_ad_a}{R_b} \) = \( \frac{45 lbs. \times 7 ft.}{55 lbs.} \) = \( \frac{315 ft⋅lb}{55 lbs.} \) = 5.73 ft.
A fixed pulley has a mechanical advantage of:
-1 |
|
1 |
|
2 |
|
0 |
A fixed pulley is used to change the direction of a force and does not multiply the force applied. As such, it has a mechanical advantage of one. The benefit of a fixed pulley is that it can allow the force to be applied at a more convenient angle, for example, pulling downward or horizontally to lift an object instead of upward.
| 52.5 lbs. | |
| 60.3 lbs. | |
| 58.3 lbs. | |
| 116.7 lbs. |
This problem describes an inclined plane and, for an inclined plane, the effort force multiplied by the effort distance equals the resistance force multipied by the resistance distance:
Fede = Frdr
Plugging in the variables from this problem yields:
Fe x 12 ft. = 350 lbs. x 2 ft.
Fe = \( \frac{700 ft⋅lb}{12 ft.} \) = 58.3 lbs.