| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.04 |
| Score | 0% | 61% |
The mechanical advantage of a wheel and axle is equal to the:
length of the axle |
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difference in the lengths of the axles |
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difference in the diameters of the wheels |
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ratio of the diameters of the wheels |
A wheel and axle uses two different diameter wheels mounted to a connecting axle. Force is applied to the larger wheel and large movements of this wheel result in small movements in the smaller wheel. Because a larger movement distance is being translated to a smaller distance, force is increased with a mechanical advantage equal to the ratio of the diameters of the wheels. An example of a wheel and axle is the steering wheel of a car.
Which of the following is the formula for gravitational potential energy?
\(PE = { 1 \over 2} mv^2\) |
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\(PE = mg^2h\) |
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\(PE = mgh\) |
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\(PE = { 1 \over 2} mg^2\) |
Gravitational potential energy is energy by virtue of gravity. The higher an object is raised above a surface the greater the distance it must fall to reach that surface and the more velocity it will build as it falls. For gravitational potential energy, PE = mgh where m is mass (kilograms), h is height (meters), and g is acceleration due to gravity which is a constant (9.8 m/s2).
Friction resists movement in a direction __________ to the movement.
opposite |
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normal |
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parallel |
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perpendicular |
Friction resists movement. Kinetic (also called sliding or dynamic) friction resists movement in a direction opposite to the movement. Because it opposes movement, kinetic friction will eventually bring an object to a stop. An example is a rock that's sliding across ice.
| 162 lbs. | |
| 54 lbs. | |
| 13.5 lbs. | |
| 216 lbs. |
fAdA = fBdB + fCdC
For this problem, this equation becomes:
35 lbs. x 10 ft. = 40 lbs. x 2 ft. + fC x 5 ft.
350 ft. lbs. = 80 ft. lbs. + fC x 5 ft.
fC = \( \frac{350 ft. lbs. - 80 ft. lbs.}{5 ft.} \) = \( \frac{270 ft. lbs.}{5 ft.} \) = 54 lbs.
| 2.0 | |
| 5 | |
| -5 | |
| 10 |
The mechanical advantage of a wheel and axle is the input radius divided by the output radius:
MA = \( \frac{r_i}{r_o} \)
In this case, the input radius (where the effort force is being applied) is 10 and the output radius (where the resistance is being applied) is 5 for a mechanical advantage of \( \frac{10}{5} \) = 2.0