ASVAB Mechanical Comprehension Practice Test 49007 Results

Your Results Global Average
Questions 5 5
Correct 0 3.36
Score 0% 67%

Review

1

On Earth, acceleration due to gravity (g) is approximately __________. 

81% Answer Correctly

6.67 x 10-11 m/s2

9.8 m/s2

1 m/s2

1 m/s


Solution

Newton's Law of Univeral Gravitation defines the general formula for the attraction of gravity between two objects:  \(\vec{F_{g}} = { Gm_{1}m_{2} \over r^2}\) . In the specific case of an object falling toward Earth, the acceleration due to gravity (g) is approximately 9.8 m/s2


2

Which of the following is not a type of structural load?

50% Answer Correctly

dead load

wind load

live load

occupancy load


Solution

Dead load is the weight of the building and materials, live load is additional weight due to occupancy or use, snow load is the weight of accumulated snow on a structure and wind load is the force of wind pressures against structure surfaces.


3

What type of load acts on a relatively small area of a structure?

74% Answer Correctly

non-uniformly distributed load

concentrated load

dynamic load

impact load


Solution

A concentrated load acts on a relatively small area of a structure, a static uniformly distributed load doesn't create specific stress points or vary with time, a dynamic load varies with time or affects a structure that experiences a high degree of movement, an impact load is sudden and for a relatively short duration and a non-uniformly distributed load creates different stresses at different locations on a structure.


4 A mass of air has a pressure of 12.0 psi and a volume of 60 ft.3. If the air is compressed to a new volume of 40 ft.3, what is the new pressure?
56% Answer Correctly
54 psi
18 psi
9 psi
24 psi

Solution

According to Boyle's Law, pressure and volume are inversely proportional:

\( \frac{P_1}{P_2} \) = \( \frac{V_2}{V_1} \)

In this problem, V2 = 40 ft.3, V1 = 60 ft.3 and P1 = 12.0 psi. Solving for P2:

P2 = \( \frac{P_1}{\frac{V_2}{V_1}} \) = \( \frac{12.0 psi}{\frac{40 ft.^3}{60 ft.^3}} \) = 18 psi


5 If you have a gear train with two gears, the first with 20 teeth and the second with 8 teeth, how many revolutions does the second gear make for each revolution of the first gear?
77% Answer Correctly
4
2.5
5
4.5

Solution

The gear ratio (Vr) of a gear train is the product of the gear ratios between the pairs of meshed gears. Let N represent the number of teeth for each gear:

Vr = \( \frac{N_1}{N_2} \) \( \frac{N_2}{N_3} \) \( \frac{N_3}{N_4} \) ... \( \frac{N_n}{N_{n+1}} \)

In this problem, we have only two gears so the equation becomes:

Vr = \( \frac{N_1}{N_2} \) = \( \frac{20}{8} \) = 2.5