ASVAB Mechanical Comprehension Practice Test 496678 Results

	Your Results	Global Average
Questions	5	5
Correct	0	3.46
Score	0%	69%

Review

Drag is a type of:

81% Answer Correctly

	kinetic energy
	work
	potential energy
	friction

Solution

Drag is friction that opposes movement through a fluid like liquid or air. The amount of drag depends on the shape and speed of the object with slower objects experiencing less drag than faster objects and more aerodynamic objects experiencing less drag than those with a large leading surface area.

2 If A = 6 ft. and the green box weighs 30 lbs. what is the torque acting on the A side of this lever?

74% Answer Correctly

	360 ft⋅lb
	60 ft⋅lb
	180 ft⋅lb
	720 ft⋅lb

Solution

For a lever, torque is weight x distance from the fulcrum which, in this case, is: 30 ft. x 6 lbs. = 180 ft⋅lb

3 80 lbs. of effort is used by a machine to lift a 320 lbs. box. What is the mechanical advantage of the machine?

84% Answer Correctly

	4
	3.6
	5.5
	4.4

Solution

Mechanical advantage is resistance force divided by effort force:

MA = \( \frac{F_r}{F_e} \) = \( \frac{320 lbs.}{80 lbs.} \) = 4

Lisa lifts a 25 pound box from the floor onto a loading dock 4 ft. off the ground. Sam slides the same box along a ramp to move it up another 4 ft. onto a flatbed truck. Who has done more work?

50% Answer Correctly

	Lisa
	They have done an equal amount of work
	Sam
	Neither have done any work

Solution

Work is force multiplied by distance. Because both Connie and Sam moved the same weight the same distance they have done an equal amount of work. Sam employed the mechnacial advantage of an inclined plane so he exerted less effort to do the work but the amount of work done was still the same.

Which of the following is the formula for hydraulic pressure?

58% Answer Correctly

	P = FA
	P = F/A²
	P = F/A
	P = FA²

Solution

Hydraulics is the transmission of force through the use of liquids. Liquids are especially suited for transferring force in complex machines because they compress very little and can occupy very small spaces. Hydraulic pressure is calculated by dividing force by the area over which it is applied: P = F/A where F is force in pounds, A is area in square inches, and the resulting pressure is in pounds per square inch (psi).