| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.28 |
| Score | 0% | 66% |
When all forces acting on a system cancel each other out, this is called:
potential energy |
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equilibrium |
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rest |
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stasis |
When a system is stable or balanced (equilibrium) all forces acting on the system cancel each other out. In the case of torque, equilibrium means that the sum of the anticlockwise moments about a center of rotation equal the sum of the clockwise moments.
On Earth, acceleration due to gravity (g) is approximately __________.
9.8 m/s2 |
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1 m/s2 |
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1 m/s |
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6.67 x 10-11 m/s2 |
Newton's Law of Univeral Gravitation defines the general formula for the attraction of gravity between two objects: \(\vec{F_{g}} = { Gm_{1}m_{2} \over r^2}\) . In the specific case of an object falling toward Earth, the acceleration due to gravity (g) is approximately 9.8 m/s2.
A fixed pulley is useful for which of the following?
changing the direction of the input force |
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multiplying the input distance |
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changing the direction of the output force |
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multiplying the input force |
A fixed pulley is used to change the direction of a force and does not multiply the force applied. As such, it has a mechanical advantage of one. The benefit of a fixed pulley is that it can allow the force to be applied at a more convenient angle, for example, pulling downward or horizontally to lift an object instead of upward.
Which of the following will increase the mechanical advantage of a second-class lever?
decrease the length of the lever |
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move the object being lifted closer to the fulcrum |
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move the object being lifted farther away from the fulcrum |
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move the fulcrum between the force and the object being lifted |
A second-class lever is used to increase force on an object in the same direction as the force is applied. This lever requires a smaller force to lift a larger load but the force must be applied over a greater distance. The fulcrum is placed at one end of the lever and mechanical advantage increases as the object being lifted is moved closer to the fulcrum or the length of the lever is increased. An example of a second-class lever is a wheelbarrow.
| 20.6 psi | |
| 18.5 psi | |
| 23.6 psi | |
| 30.9 psi |
According to Boyle's Law, pressure and volume are inversely proportional:
\( \frac{P_1}{P_2} \) = \( \frac{V_2}{V_1} \)
In this problem, V2 = 35 ft.3, V1 = 60 ft.3 and P1 = 12.0 psi. Solving for P2:
P2 = \( \frac{P_1}{\frac{V_2}{V_1}} \) = \( \frac{12.0 psi}{\frac{35 ft.^3}{60 ft.^3}} \) = 20.6 psi