| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.89 |
| Score | 0% | 58% |
| 254 lbs. | |
| 247 lbs. | |
| 237 lbs. | |
| 245 lbs. |
This problem describes an inclined plane and, for an inclined plane, the effort force multiplied by the effort distance equals the resistance force multipied by the resistance distance:
Fede = Frdr
Plugging in the variables from this problem yields:
Fe x 6 ft. = 490 lbs. x 3 ft.
Fe = \( \frac{1470 ft⋅lb}{6 ft.} \) = 245 lbs.
| 8 | |
| 1.14 | |
| 1 | |
| 7 |
The mechanical advantage of a wheel and axle is the input radius divided by the output radius:
MA = \( \frac{r_i}{r_o} \)
In this case, the input radius (where the effort force is being applied) is 8 and the output radius (where the resistance is being applied) is 7 for a mechanical advantage of \( \frac{8}{7} \) = 1.14
A fixed pulley has a mechanical advantage of:
0 |
|
1 |
|
2 |
|
-1 |
A fixed pulley is used to change the direction of a force and does not multiply the force applied. As such, it has a mechanical advantage of one. The benefit of a fixed pulley is that it can allow the force to be applied at a more convenient angle, for example, pulling downward or horizontally to lift an object instead of upward.
Which of the following is not a characteristic of a ceramic?
low corrosive action |
|
chemically stable |
|
high melting point |
|
low density |
Ceramics are mixtures of metallic and nonmetallic elements that withstand exteme thermal, chemical, and pressure environments. They have a high melting point, low corrosive action, and are chemically stable. Examples include rock, sand, clay, glass, brick, and porcelain.
| 1.36 ft. | |
| 2.73 ft. | |
| 0 ft. | |
| 8.18 ft. |
To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.Solving for da, our missing value, and plugging in our variables yields:
da = \( \frac{R_bd_b}{R_a} \) = \( \frac{50 lbs. \times 3 ft.}{55 lbs.} \) = \( \frac{150 ft⋅lb}{55 lbs.} \) = 2.73 ft.