| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.83 |
| Score | 0% | 57% |
Two gears are connected and the larger gear drives the smaller gear. The speed of rotation will __________ and the torque will __________.
increase, increase |
|
increase, decrease |
|
decrease, decrease |
|
decrease, increase |
Connected gears of different numbers of teeth are used together to change the rotational speed and torque of the input force. If the smaller gear drives the larger gear, the speed of rotation will be reduced and the torque will increase. If the larger gear drives the smaller gear, the speed of rotation will increase and the torque will be reduced.
| 8 ft. | |
| 16 ft. | |
| 57 ft. | |
| 4 ft. |
Win = Wout
Feffort x deffort = Fresistance x dresistance
In this problem, the effort work is 920 ft⋅lb and the resistance force is 230 lbs. and we need to calculate the resistance distance:
Win = Fresistance x dresistance
920 ft⋅lb = 230 lbs. x dresistance
dresistance = \( \frac{920ft⋅lb}{230 lbs.} \) = 4 ft.
Depending on where you apply effort and resistance, the wheel and axle can multiply:
power or distance |
|
force or distance |
|
speed or power |
|
force or speed |
If you apply the resistance to the axle and the effort to the wheel, the wheel and axle will multiply force and if you apply the resistance to the wheel and the effort to the axle, it will multiply speed.
The principle of conservation of mechanical energy states that, as long as no other forces are applied, what will remain constant as an object falls?
acceleration |
|
potential energy |
|
kinetic energy |
|
total mechanical energy |
As an object falls, its potential energy is converted into kinetic energy. The principle of conservation of mechanical energy states that, as long as no other forces are applied, total mechanical energy (PE + KE) of the object will remain constant at all points in its descent.
| 0 ft. | |
| 3.5 ft. | |
| 7 ft. | |
| 14 ft. |
To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.Solving for db, our missing value, and plugging in our variables yields:
db = \( \frac{R_ad_a}{R_b} \) = \( \frac{35 lbs. \times 7 ft.}{70 lbs.} \) = \( \frac{245 ft⋅lb}{70 lbs.} \) = 3.5 ft.