| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.26 |
| Score | 0% | 65% |
Potential energy is energy that has the potential to be converted into what?
power |
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work |
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heat |
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kinetic energy |
Potential energy is the energy of an object by virtue of its position relative to other objects. It is energy that has the potential to be converted into kinetic energy.
| 1.43 ft. | |
| 0.95 ft. | |
| 2.86 ft. | |
| 17 ft. |
fAdA = fBdB
For this problem, the equation becomes:
50 lbs. x 4 ft. = 70 lbs. x dB
dB = \( \frac{50 \times 4 ft⋅lb}{70 lbs.} \) = \( \frac{200 ft⋅lb}{70 lbs.} \) = 2.86 ft.
Which of the following is the formula for gravitational potential energy?
\(PE = { 1 \over 2} mv^2\) |
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\(PE = { 1 \over 2} mg^2\) |
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\(PE = mg^2h\) |
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\(PE = mgh\) |
Gravitational potential energy is energy by virtue of gravity. The higher an object is raised above a surface the greater the distance it must fall to reach that surface and the more velocity it will build as it falls. For gravitational potential energy, PE = mgh where m is mass (kilograms), h is height (meters), and g is acceleration due to gravity which is a constant (9.8 m/s2).
A wedge converts force applied to its blunt end into force __________ its inclined surface.
along |
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perpendicular to |
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opposite to |
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parallel to |
The wedge is a moving inclined plane that is used to lift, hold, or break apart an object. A wedge converts force applied to its blunt end into force perpendicular to its inclined surface. In contrast to a stationary plane where force is applied to the object being moved, with a wedge the object is stationary and the force is being applied to the plane. Examples of a wedge include knives and chisels.
| 16.25 lbs. | |
| 48.75 lbs. | |
| 12.19 lbs. | |
| 146.25 lbs. |
To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.Solving for Rb, our missing value, and plugging in our variables yields:
Rb = \( \frac{R_ad_a}{d_b} \) = \( \frac{65 lbs. \times 6 ft.}{8 ft.} \) = \( \frac{390 ft⋅lb}{8 ft.} \) = 48.75 lbs.