| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.02 |
| Score | 0% | 60% |
What type of load varies with time or affects a structure that experiences a high degree of movement?
dynamic load |
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static load |
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impact load |
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concentrated load |
A concentrated load acts on a relatively small area of a structure, a static uniformly distributed load doesn't create specific stress points or vary with time, a dynamic load varies with time or affects a structure that experiences a high degree of movement, an impact load is sudden and for a relatively short duration and a non-uniformly distributed load creates different stresses at different locations on a structure.
Concurrent forces:
act along the same line of action |
|
pass through a common point |
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act in a common plane |
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act in a common dimension |
Collinear forces act along the same line of action, concurrent forces pass through a common point and coplanar forces act in a common plane.
| 9 | |
| 8.1 | |
| 9.9 | |
| 18 |
Mechanical advantage (MA) can be calculated knowing only the distance the effort (blue arrow) moves and the distance the resistance (green box) moves. The equation is:
MA = \( \frac{E_d}{R_d} \)
where Ed is the effort distance and Rd is the resistance distance. For this problem, the equation becomes:
MA = \( \frac{2 ft.}{0.22 ft.} \) = 9
You might be wondering how having an effort distance of 9 times the resistance distance is an advantage. Remember the principle of moments. For a lever in equilibrium the effort torque equals the resistance torque. Because torque is force x distance, if the effort distance is 9 times the resistance distance, the effort force must be \( \frac{1}{9} \) the resistance force. You're trading moving 9 times the distance for only having to use \( \frac{1}{9} \) the force.
| 35.83 lbs. | |
| 71.67 lbs. | |
| 17.92 lbs. | |
| 0 lbs. |
fAdA = fBdB + fCdC
For this problem, this equation becomes:
35 lbs. x 10 ft. = 45 lbs. x 3 ft. + fC x 6 ft.
350 ft. lbs. = 135 ft. lbs. + fC x 6 ft.
fC = \( \frac{350 ft. lbs. - 135 ft. lbs.}{6 ft.} \) = \( \frac{215 ft. lbs.}{6 ft.} \) = 35.83 lbs.
The force amplification achieved by using a tool, mechanical device or machine system is called:
power |
|
work |
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mechanical advantage |
|
efficiency |
Mechanical advantage is a measure of the force amplification achieved by using a tool, mechanical device or machine system. Such a device utilizes input force and trades off forces against movement to amplify and/or change its direction.