| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.11 |
| Score | 0% | 62% |
| 7.43 ft. | |
| 0 ft. | |
| 3.71 ft. | |
| 1.86 ft. |
To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.Solving for db, our missing value, and plugging in our variables yields:
db = \( \frac{R_ad_a}{R_b} \) = \( \frac{65 lbs. \times 1 ft.}{35 lbs.} \) = \( \frac{65 ft⋅lb}{35 lbs.} \) = 1.86 ft.
| 50 ft⋅lb | |
| 150 ft⋅lb | |
| 37 ft⋅lb | |
| 600 ft⋅lb |
Boyle's law defines the relationship between pressure and volume as:
\(\frac{P_1}{P_2} = \frac{V_2}{V_1}\) |
|
\(\frac{P_1}{P_2} = \frac{V_1}{V_2}\) |
|
\(\frac{P_1}{P_2} = {V_1}{V_2}\) |
|
\({P_1}{P_2} = {V_1}{V_2}\) |
Boyle's law states that "for a fixed amount of an ideal gas kept at a fixed temperature, pressure and volume are inversely proportional". Expressed as a formula, that's \(\frac{P_1}{P_2} = \frac{V_2}{V_1}\)
Connected gears of different numbers of teeth are used together to change which of the following charasteristics of the input force?
energy |
|
force |
|
torque |
|
rotational direction |
Connected gears of different numbers of teeth are used together to change the rotational speed and torque of the input force. If the smaller gear drives the larger gear, the speed of rotation will be reduced and the torque will increase. If the larger gear drives the smaller gear, the speed of rotation will increase and the torque will be reduced.
| 98 ft. | |
| 49 ft. | |
| 24.5 ft. | |
| 12.25 ft. |
To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.Solving for da, our missing value, and plugging in our variables yields:
da = \( \frac{R_bd_b}{R_a} \) = \( \frac{70 lbs. \times 7 ft.}{10 lbs.} \) = \( \frac{490 ft⋅lb}{10 lbs.} \) = 49 ft.