ASVAB Mechanical Comprehension Practice Test 571707 Results

Your Results Global Average
Questions 5 5
Correct 0 3.11
Score 0% 62%

Review

1 If the green box weighs 65 lbs. and is 1 ft. from the fulcrum, how far from the fulcrum would a 35 lbs. force need to be applied to balance the lever?
58% Answer Correctly
7.43 ft.
0 ft.
3.71 ft.
1.86 ft.

Solution

To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.

Solving for db, our missing value, and plugging in our variables yields:

db = \( \frac{R_ad_a}{R_b} \) = \( \frac{65 lbs. \times 1 ft.}{35 lbs.} \) = \( \frac{65 ft⋅lb}{35 lbs.} \) = 1.86 ft.


2 If A = 5 ft. and the green box weighs 30 lbs. what is the torque acting on the A side of this lever?
75% Answer Correctly
50 ft⋅lb
150 ft⋅lb
37 ft⋅lb
600 ft⋅lb

Solution
For a lever, torque is weight x distance from the fulcrum which, in this case, is: 30 ft. x 5 lbs. = 150 ft⋅lb

3

Boyle's law defines the relationship between pressure and volume as:

58% Answer Correctly

\(\frac{P_1}{P_2} = \frac{V_2}{V_1}\)

\(\frac{P_1}{P_2} = \frac{V_1}{V_2}\)

\(\frac{P_1}{P_2} = {V_1}{V_2}\)

\({P_1}{P_2} = {V_1}{V_2}\)


Solution

Boyle's law states that "for a fixed amount of an ideal gas kept at a fixed temperature, pressure and volume are inversely proportional". Expressed as a formula, that's \(\frac{P_1}{P_2} = \frac{V_2}{V_1}\)


4

Connected gears of different numbers of teeth are used together to change which of the following charasteristics of the input force?

65% Answer Correctly

energy

force

torque

rotational direction


Solution

Connected gears of different numbers of teeth are used together to change the rotational speed and torque of the input force. If the smaller gear drives the larger gear, the speed of rotation will be reduced and the torque will increase. If the larger gear drives the smaller gear, the speed of rotation will increase and the torque will be reduced.


5 If the green box weighs 10 lbs. and 70 lbs. of force is applied 7 ft. from the fulcrum at the blue arrow, how far from the fulcrum would the green box need to be placed to balance the lever?
55% Answer Correctly
98 ft.
49 ft.
24.5 ft.
12.25 ft.

Solution

To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.

Solving for da, our missing value, and plugging in our variables yields:

da = \( \frac{R_bd_b}{R_a} \) = \( \frac{70 lbs. \times 7 ft.}{10 lbs.} \) = \( \frac{490 ft⋅lb}{10 lbs.} \) = 49 ft.