| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.98 |
| Score | 0% | 60% |
| 9.5 | |
| 7.2 | |
| 8 | |
| 4 |
The mechanical advantage (MA) of an inclined plane is the effort distance divided by the resistance distance. In this case, the effort distance is the length of the ramp and the resistance distance is the height of the green box:
MA = \( \frac{d_e}{d_r} \) = \( \frac{32 ft.}{4 ft.} \) = 8
| 687.5 \( \frac{ft⋅lb}{s} \) | |
| 5 \( \frac{ft⋅lb}{s} \) | |
| 229.2 \( \frac{ft⋅lb}{s} \) | |
| 343.8 \( \frac{ft⋅lb}{s} \) |
An inclined plane increases ___________ to reduce ____________.
force, power |
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distance, power |
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distance, force |
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force, distance |
An inclined plane is a simple machine that reduces the force needed to raise an object to a certain height. Work equals force x distance and, by increasing the distance that the object travels, an inclined plane reduces the force necessary to raise it to a particular height. In this case, the mechanical advantage is to make the task easier. An example of an inclined plane is a ramp.
If the handles of a wheelbarrow are 3 ft. from the wheel axle, what force must you exert to lift the handles if it's carrying a 270 lb. load concentrated at a point 0.5 ft. from the axle?
0.83 lbs |
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810 lbs |
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90 lbs |
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45 lbs |
This problem describes a second-class lever and, for a second class lever, the effort force multiplied by the effort distance equals the resistance force multipied by the resistance distance: Fede = Frdr. Plugging in the variables from this problem yields:
Fe x 3 ft. = 270 lbs x 0.5 ft
Fe = 135 ft-lb. / 3 ft
Fe = 45 lbs
What is the first step to solving a problem where multiple forces are acting on an object?
calculate the total force |
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calculate potential energy |
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calculate kinetic energy |
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calculate the net force |
In mechanics, multiple forces are often acting on a particular object and, taken together, produce the net force acting on that object. Like force, net force is a vector quantity in that it has magnitude and direction.