ASVAB Mechanical Comprehension Practice Test 58783 Results

Your Results Global Average
Questions 5 5
Correct 0 2.93
Score 0% 59%

Review

1

Which of these is the formula for kinetic energy?

67% Answer Correctly

\(KE = mgh\)

\(KE = {1 \over 2}mv^2\)

\(KE = {m \over v^2 }\)

\(KE = {1 \over 2}mh^2\)


Solution

Kinetic energy is the energy of movement and is a function of the mass of an object and its speed: \(KE = {1 \over 2}mv^2\) where m is mass in kilograms, v is speed in meters per second, and KE is in joules. The most impactful quantity to kinetic energy is velocity as an increase in mass increases KE linearly while an increase in speed increases KE exponentially.


2

An inclined plane increases ___________ to reduce ____________.

58% Answer Correctly

force, distance

distance, power

distance, force

force, power


Solution

An inclined plane is a simple machine that reduces the force needed to raise an object to a certain height. Work equals force x distance and, by increasing the distance that the object travels, an inclined plane reduces the force necessary to raise it to a particular height. In this case, the mechanical advantage is to make the task easier. An example of an inclined plane is a ramp.


3

Which of the following represents how much two materials resist sliding across each other?

53% Answer Correctly

kinetic friction

coefficient of friction

normal friction

static friction


Solution

Coefficient of friction (μ) represents how much two materials resist sliding across each other.  Smooth surfaces like ice have low coefficients of friction while rough surfaces like concrete have high μ.


4

For any given surface, the coefficient of static friction is ___________ the coefficient of kinetic friction.

54% Answer Correctly

equal to

higher than

lower than

opposite


Solution

For any given surface, the coefficient of static friction is higher than the coefficient of kinetic friction. More force is required to initally get an object moving than is required to keep it moving. Additionally, static friction only arises in response to an attempt to move an object (overcome the normal force between it and the surface).


5 If the green box weighs 20 lbs. and is 7 ft. from the fulcrum, how much force would need to be applied at the blue arrow to balance the lever if the arrow's distance from the fulcrum is 9 ft.?
62% Answer Correctly
62.22 lbs.
0 lbs.
3.89 lbs.
15.56 lbs.

Solution

To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.

Solving for Rb, our missing value, and plugging in our variables yields:

Rb = \( \frac{R_ad_a}{d_b} \) = \( \frac{20 lbs. \times 7 ft.}{9 ft.} \) = \( \frac{140 ft⋅lb}{9 ft.} \) = 15.56 lbs.