| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.02 |
| Score | 0% | 60% |
The principle of moments defines equilibrium in terms of:
power |
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speed |
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energy |
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torque |
According to the principle of moments, you can maintain equilibrium if the moments (forces) tending to clockwise rotation are equal to the moments tending to counterclockwise rotation. Another name for these moments of force is torque.
| 10 lbs. | |
| 2.5 lbs. | |
| 30 lbs. | |
| 0 lbs. |
To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.Solving for Rb, our missing value, and plugging in our variables yields:
Rb = \( \frac{R_ad_a}{d_b} \) = \( \frac{50 lbs. \times 1 ft.}{5 ft.} \) = \( \frac{50 ft⋅lb}{5 ft.} \) = 10 lbs.
| 6300 ft⋅lb | |
| 3150ft⋅lb | |
| 1575ft⋅lb | |
| 25200ft⋅lb |
A shovel is an example of which class of lever?
a shovel is not a lever |
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first |
|
second |
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third |
A third-class lever is used to increase distance traveled by an object in the same direction as the force applied. The fulcrum is at one end of the lever, the object at the other, and the force is applied between them. This lever does not impart a mechanical advantage as the effort force must be greater than the load but does impart extra speed to the load. Examples of third-class levers are shovels and tweezers.
| 19.6 psi | |
| 23.6 psi | |
| 20.6 psi | |
| 41.1 psi |
According to Boyle's Law, pressure and volume are inversely proportional:
\( \frac{P_1}{P_2} \) = \( \frac{V_2}{V_1} \)
In this problem, V2 = 35 ft.3, V1 = 60 ft.3 and P1 = 12.0 psi. Solving for P2:
P2 = \( \frac{P_1}{\frac{V_2}{V_1}} \) = \( \frac{12.0 psi}{\frac{35 ft.^3}{60 ft.^3}} \) = 20.6 psi