| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.92 |
| Score | 0% | 58% |
Collinear forces:
act in a common plane |
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pass through a common point |
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act along the same line of action |
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are unrelated to each other |
Collinear forces act along the same line of action, concurrent forces pass through a common point and coplanar forces act in a common plane.
Which of the following represents the force a surface exerts when an object presses against it?
mass |
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counter force |
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normal force |
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friction |
Normal force (FN) represents the force a surface exerts when an object presses against it.
Which of these will have the most impact on the kinetic energy of an object?
its direction |
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its mass |
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its weight |
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its speed |
Kinetic energy is the energy of movement and is a function of the mass of an object and its speed: \(KE = {1 \over 2}mv^2\) where m is mass in kilograms, v is speed in meters per second, and KE is in joules. The most impactful quantity to kinetic energy is velocity as an increase in mass increases KE linearly while an increase in speed increases KE exponentially.
Which of the following is the formula for hydraulic pressure?
P = F/A |
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P = FA2 |
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P = FA |
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P = F/A2 |
Hydraulics is the transmission of force through the use of liquids. Liquids are especially suited for transferring force in complex machines because they compress very little and can occupy very small spaces. Hydraulic pressure is calculated by dividing force by the area over which it is applied: P = F/A where F is force in pounds, A is area in square inches, and the resulting pressure is in pounds per square inch (psi).
| 0 lbs. | |
| 10 lbs. | |
| 30 lbs. | |
| 20 lbs. |
To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.Solving for Ra, our missing value, and plugging in our variables yields:
Ra = \( \frac{R_bd_b}{d_a} \) = \( \frac{5 lbs. \times 8 ft.}{4 ft.} \) = \( \frac{40 ft⋅lb}{4 ft.} \) = 10 lbs.