ASVAB Mechanical Comprehension Practice Test 655244 Results

Your Results Global Average
Questions 5 5
Correct 0 2.64
Score 0% 53%

Review

1

Torque involves a perpendicular force applied to a lever arm that moves around a center of rotation. Increasing the length of the lever arm will do which of the following?

54% Answer Correctly

increase torque

decrease torque

decrease applied force

increase applied force


Solution

Torque measures force applied during rotation: τ = rF.  Torque (τ, the Greek letter tau) = the radius of the lever arm (r) multiplied by the force (F) applied. Radius is measured from the center of rotation or fulcrum to the point at which the perpendicular force is being applied. The resulting unit for torque is newton-meter (N-m) or foot-pound (ft-lb).


2

Force of friction due to kinetic friction is __________ the force of friction due to static friction.

40% Answer Correctly

higher than

opposite

the same as

lower than


Solution

The formula for force of friction (Ff) is the same whether kinetic or static friction applies: Ff = μFN. To distinguish between kinetic and static friction, μk and μs are often used in place of μ.


3

A wedge converts force applied to its blunt end into force __________ its inclined surface.

57% Answer Correctly

parallel to

opposite to

perpendicular to

along


Solution

The wedge is a moving inclined plane that is used to lift, hold, or break apart an object. A wedge converts force applied to its blunt end into force perpendicular to its inclined surface. In contrast to a stationary plane where force is applied to the object being moved, with a wedge the object is stationary and the force is being applied to the plane. Examples of a wedge include knives and chisels.


4

Specific gravity is a comparison of the density of an object with the density of:

57% Answer Correctly

carbon

air

water

oil


Solution

Specific gravity is the ratio of the density of equal volumes of a substance and water and is measured by a hyrdometer.


5 A mass of air has a pressure of 9.0 psi and a volume of 45 ft.3. If the air is compressed to a new volume of 30 ft.3, what is the new pressure?
56% Answer Correctly
20.3 psi
13.5 psi
14.9 psi
15.5 psi

Solution

According to Boyle's Law, pressure and volume are inversely proportional:

\( \frac{P_1}{P_2} \) = \( \frac{V_2}{V_1} \)

In this problem, V2 = 30 ft.3, V1 = 45 ft.3 and P1 = 9.0 psi. Solving for P2:

P2 = \( \frac{P_1}{\frac{V_2}{V_1}} \) = \( \frac{9.0 psi}{\frac{30 ft.^3}{45 ft.^3}} \) = 13.5 psi