| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.87 |
| Score | 0% | 57% |
Which of the following will increase the mechanical advantage of this inclined plane?
lengthen the ramp |
|
increase the force acting at the blue arrow |
|
shorten the ramp |
|
lower the force acting at the blue arrow |
The mechanical advantage (MA) of an inclined plane is the effort distance divided by the resistance distance. In order to increase mechanical advantage, this ratio must increase which means making the effort distance longer and this can be accomplished by lengthening the length of the ramp.
| 65% | |
| 0% | |
| 260% | |
| 16% |
Which of the following is not a type of structural load?
live load |
|
wind load |
|
occupancy load |
|
dead load |
Dead load is the weight of the building and materials, live load is additional weight due to occupancy or use, snow load is the weight of accumulated snow on a structure and wind load is the force of wind pressures against structure surfaces.
A box is resting on a smooth floor. Static friction is present:
at all times |
|
only if normal force is present |
|
if the coefficient of friction is greater than one |
|
when an attempt is made to move the box |
For any given surface, the coefficient of static friction is higher than the coefficient of kinetic friction. More force is required to initally get an object moving than is required to keep it moving. Additionally, static friction only arises in response to an attempt to move an object (overcome the normal force between it and the surface).
| 46.9 lbs. | |
| 31.3 lbs. | |
| 32.8 lbs. | |
| 34.3 lbs. |
This problem describes an inclined plane and, for an inclined plane, the effort force multiplied by the effort distance equals the resistance force multipied by the resistance distance:
Fede = Frdr
Plugging in the variables from this problem yields:
Fe x 16 ft. = 250 lbs. x 2 ft.
Fe = \( \frac{500 ft⋅lb}{16 ft.} \) = 31.3 lbs.