| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.13 |
| Score | 0% | 63% |
Specific gravity is a comparison of the density of an object with the density of:
air |
|
oil |
|
water |
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carbon |
Specific gravity is the ratio of the density of equal volumes of a substance and water and is measured by a hyrdometer.
The principle of conservation of mechanical energy states that, as long as no other forces are applied, what will remain constant as an object falls?
kinetic energy |
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total mechanical energy |
|
acceleration |
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potential energy |
As an object falls, its potential energy is converted into kinetic energy. The principle of conservation of mechanical energy states that, as long as no other forces are applied, total mechanical energy (PE + KE) of the object will remain constant at all points in its descent.
On Earth, acceleration due to gravity (g) is approximately __________.
9.8 m/s2 |
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1 m/s |
|
1 m/s2 |
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6.67 x 10-11 m/s2 |
Newton's Law of Univeral Gravitation defines the general formula for the attraction of gravity between two objects: \(\vec{F_{g}} = { Gm_{1}m_{2} \over r^2}\) . In the specific case of an object falling toward Earth, the acceleration due to gravity (g) is approximately 9.8 m/s2.
Normal force is generally equal to the __________ of an object.
weight |
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coefficient of friction |
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density |
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mass |
Normal force arises on a flat horizontal surface in response to an object's weight pressing it down. Consequently, normal force is generally equal to the object's weight.
| 3.75 lbs. | |
| 0.94 lbs. | |
| 1.25 lbs. | |
| 7.5 lbs. |
To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.Solving for Rb, our missing value, and plugging in our variables yields:
Rb = \( \frac{R_ad_a}{d_b} \) = \( \frac{30 lbs. \times 1 ft.}{8 ft.} \) = \( \frac{30 ft⋅lb}{8 ft.} \) = 3.75 lbs.