ASVAB Mechanical Comprehension Practice Test 706207 Results

Your Results Global Average
Questions 5 5
Correct 0 3.13
Score 0% 63%

Review

1

Specific gravity is a comparison of the density of an object with the density of:

57% Answer Correctly

air

oil

water

carbon


Solution

Specific gravity is the ratio of the density of equal volumes of a substance and water and is measured by a hyrdometer.


2

The principle of conservation of mechanical energy states that, as long as no other forces are applied, what will remain constant as an object falls?

45% Answer Correctly

kinetic energy

total mechanical energy

acceleration

potential energy


Solution

As an object falls, its potential energy is converted into kinetic energy. The principle of conservation of mechanical energy states that, as long as no other forces are applied, total mechanical energy (PE + KE) of the object will remain constant at all points in its descent.


3

On Earth, acceleration due to gravity (g) is approximately __________. 

81% Answer Correctly

9.8 m/s2

1 m/s

1 m/s2

6.67 x 10-11 m/s2


Solution

Newton's Law of Univeral Gravitation defines the general formula for the attraction of gravity between two objects:  \(\vec{F_{g}} = { Gm_{1}m_{2} \over r^2}\) . In the specific case of an object falling toward Earth, the acceleration due to gravity (g) is approximately 9.8 m/s2. 


4

Normal force is generally equal to the __________ of an object.

61% Answer Correctly

weight

coefficient of friction

density

mass


Solution

Normal force arises on a flat horizontal surface in response to an object's weight pressing it down. Consequently, normal force is generally equal to the object's weight.


5 If the green box weighs 30 lbs. and is 1 ft. from the fulcrum, how much weight would need to be placed at the blue arrow to balance the lever if the arrow's distance from the fulcrum is 8 ft.?
63% Answer Correctly
3.75 lbs.
0.94 lbs.
1.25 lbs.
7.5 lbs.

Solution

To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.

Solving for Rb, our missing value, and plugging in our variables yields:

Rb = \( \frac{R_ad_a}{d_b} \) = \( \frac{30 lbs. \times 1 ft.}{8 ft.} \) = \( \frac{30 ft⋅lb}{8 ft.} \) = 3.75 lbs.