ASVAB Mechanical Comprehension Practice Test 707037 Results

Your Results Global Average
Questions 5 5
Correct 0 2.76
Score 0% 55%

Review

1

Which of the following is not a type of structural load?

49% Answer Correctly

wind load

occupancy load

live load

dead load
Solution

Dead load is the weight of the building and materials, live load is additional weight due to occupancy or use, snow load is the weight of accumulated snow on a structure and wind load is the force of wind pressures against structure surfaces.

2 How much work can a 5 hp engine do in 4 seconds?
53% Answer Correctly
2 ft⋅lb
11000 ft⋅lb
20 ft⋅lb
1 ft⋅lb
Solution
Horsepower (hp) is a common measure of power output for complex machines. By definition, a 1 hp machine does 550 ft⋅lb of work in 1 second: 1 hp = 550 ft⋅lb/s. Substituting the variables for this problem gives us:
\( W = 5 hp \times 550 \frac{ft⋅lb}{s} \times 4s = 11000 ft⋅lb \)
3

The principle of conservation of mechanical energy states that, as long as no other forces are applied, what will remain constant as an object falls?

45% Answer Correctly

acceleration

kinetic energy

total mechanical energy

potential energy
Solution

As an object falls, its potential energy is converted into kinetic energy. The principle of conservation of mechanical energy states that, as long as no other forces are applied, total mechanical energy (PE + KE) of the object will remain constant at all points in its descent.

4

An inclined plane increases ___________ to reduce ____________.

59% Answer Correctly

force, distance

distance, power

force, power

distance, force
Solution

An inclined plane is a simple machine that reduces the force needed to raise an object to a certain height. Work equals force x distance and, by increasing the distance that the object travels, an inclined plane reduces the force necessary to raise it to a particular height. In this case, the mechanical advantage is to make the task easier. An example of an inclined plane is a ramp.

5 If you lift a 38 lbs. rock 16 ft. from the ground, how much work have you done?
71% Answer Correctly
2 ft⋅lb
608 ft⋅lb
22 ft⋅lb
1216 ft⋅lb
Solution
Work is force times distance. In this case, the force is the weight of the rock so:
\( W = F \times d \)
\( W = 38 \times 16 \)
\( W = 608 \)