Your Results | Global Average | |
---|---|---|
Questions | 5 | 5 |
Correct | 0 | 2.94 |
Score | 0% | 59% |
The mechanical advantage of a third class lever is always:
less than one |
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equal to one |
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not equal to one |
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greater than one |
A third class lever is designed to multiply distance and speed at the expense of effort force. Because the effort force is greater than the resistance, the mechanical advantage of a third class lever is always less than one.
An example of a third class lever is a broom. The fulcrum is at your hand on the end of the broom, the effort force is your other hand in the middle, and the resistance is at the bottom bristles. The effort force of your hand in the middle multiplies the distance and speed of the bristles at the bottom but at the expense of producing a brushing force that's less than the force you're applying with your hand.
Which of the following is not a type of simple machine?
screw |
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gear |
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pulley |
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lever |
The six types of simple machines are the lever, wheel and axle, pulley, inclined plane, wedge, and screw.
Which of the following is the formula for gravitational potential energy?
\(PE = { 1 \over 2} mv^2\) |
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\(PE = mg^2h\) |
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\(PE = mgh\) |
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\(PE = { 1 \over 2} mg^2\) |
Gravitational potential energy is energy by virtue of gravity. The higher an object is raised above a surface the greater the distance it must fall to reach that surface and the more velocity it will build as it falls. For gravitational potential energy, PE = mgh where m is mass (kilograms), h is height (meters), and g is acceleration due to gravity which is a constant (9.8 m/s2).
7 | |
3 | |
10 | |
7.7 |
Mechanical advantage is resistance force divided by effort force:
MA = \( \frac{F_r}{F_e} \) = \( \frac{490 lbs.}{70 lbs.} \) = 7
149.1 lbs. | |
447.3 lbs. | |
223.6 lbs. | |
164 lbs. |
This problem describes an inclined plane and, for an inclined plane, the effort force multiplied by the effort distance equals the resistance force multipied by the resistance distance:
Fede = Frdr
Plugging in the variables from this problem yields:
Fe x 11 ft. = 410 lbs. x 4 ft.
Fe = \( \frac{1640 ft⋅lb}{11 ft.} \) = 149.1 lbs.