| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.92 |
| Score | 0% | 58% |
Which of the following is the formula for hydraulic pressure?
P = F/A2 |
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P = FA2 |
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P = FA |
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P = F/A |
Hydraulics is the transmission of force through the use of liquids. Liquids are especially suited for transferring force in complex machines because they compress very little and can occupy very small spaces. Hydraulic pressure is calculated by dividing force by the area over which it is applied: P = F/A where F is force in pounds, A is area in square inches, and the resulting pressure is in pounds per square inch (psi).
What's the last gear in a gear train called?
driver gear |
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idler gear |
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output gear |
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driven gear |
A gear train is two or more gears linked together. Gear trains are designed to increase or reduce the speed or torque outpout of a rotating system or change the direction of its output. The first gear in the chain is called the driver and the last gear in the chain the driven gear with the gears between them called idler gears.
If the handles of a wheelbarrow are 3 ft. from the wheel axle, what force must you exert to lift the handles if it's carrying a 270 lb. load concentrated at a point 0.5 ft. from the axle?
0.83 lbs |
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45 lbs |
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810 lbs |
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90 lbs |
This problem describes a second-class lever and, for a second class lever, the effort force multiplied by the effort distance equals the resistance force multipied by the resistance distance: Fede = Frdr. Plugging in the variables from this problem yields:
Fe x 3 ft. = 270 lbs x 0.5 ft
Fe = 135 ft-lb. / 3 ft
Fe = 45 lbs
| 552 ft⋅lb | |
| 2 ft⋅lb | |
| 1104 ft⋅lb | |
| 0 ft⋅lb |
| 30 ft. | |
| 20 ft. | |
| 120 ft. | |
| 3 ft. |
Win = Wout
Feffort x deffort = Fresistance x dresistance
In this problem, the effort work is 180 ft⋅lb and the resistance force is 60 lbs. and we need to calculate the resistance distance:
Win = Fresistance x dresistance
180 ft⋅lb = 60 lbs. x dresistance
dresistance = \( \frac{180ft⋅lb}{60 lbs.} \) = 3 ft.