ASVAB Mechanical Comprehension Practice Test 720512 Results

Your Results Global Average
Questions 5 5
Correct 0 3.52
Score 0% 70%

Review

1 30 lbs. of effort is used by a machine to lift a 60 lbs. box. What is the mechanical advantage of the machine?
84% Answer Correctly
2
-3
10
1.8

Solution

Mechanical advantage is resistance force divided by effort force:

MA = \( \frac{F_r}{F_e} \) = \( \frac{60 lbs.}{30 lbs.} \) = 2


2

Which of the following represents how much two materials resist sliding across each other?

54% Answer Correctly

kinetic friction

static friction

normal friction

coefficient of friction


Solution

Coefficient of friction (μ) represents how much two materials resist sliding across each other.  Smooth surfaces like ice have low coefficients of friction while rough surfaces like concrete have high μ.


3

The mechanical advantage of connected gears is proportional to which characteristic of the gears?

73% Answer Correctly

speed

diameter

circumference

number of teeth


Solution

The mechanical advantage (amount of change in speed or torque) of connected gears is proportional to the number of teeth each gear has. Called gear ratio, it's the ratio of the number of teeth on the larger gear to the number of teeth on the smaller gear.  For example, a gear with 12 teeth connected to a gear with 9 teeth would have a gear ratio of 4:3.


4

A block and tackle with four pulleys would have a mechanical advantage of:

79% Answer Correctly

4

2

0

1


Solution

Two or more pulleys used together constitute a block and tackle which, unlike a fixed pulley, does impart mechanical advantage as a function of the number of pulleys that make up the arrangement.  So, for example, a block and tackle with three pulleys would have a mechanical advantage of three.


5 If 50 lbs. of force is applied 7 ft. from the fulcrum at the blue arrow and the green box is 4 ft. from the fulcrum, how much would the green box have to weigh to balance the lever?
62% Answer Correctly
87.5 lbs.
29.17 lbs.
43.75 lbs.
7 lbs.

Solution

To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.

Solving for Ra, our missing value, and plugging in our variables yields:

Ra = \( \frac{R_bd_b}{d_a} \) = \( \frac{50 lbs. \times 7 ft.}{4 ft.} \) = \( \frac{350 ft⋅lb}{4 ft.} \) = 87.5 lbs.