| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.40 |
| Score | 0% | 68% |
| 5 | |
| 10 | |
| 7 | |
| 6.5 |
Mechanical advantage is resistance force divided by effort force:
MA = \( \frac{F_r}{F_e} \) = \( \frac{100 lbs.}{20 lbs.} \) = 5
Specific gravity is a comparison of the density of an object with the density of:
water |
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air |
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oil |
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carbon |
Specific gravity is the ratio of the density of equal volumes of a substance and water and is measured by a hyrdometer.
| 16 | |
| 9.5 | |
| 8 | |
| 11 |
The gear ratio (Vr) of a gear train is the product of the gear ratios between the pairs of meshed gears. Let N represent the number of teeth for each gear:
Vr = \( \frac{N_1}{N_2} \) \( \frac{N_2}{N_3} \) \( \frac{N_3}{N_4} \) ... \( \frac{N_n}{N_{n+1}} \)
In this problem, we have only two gears so the equation becomes:Vr = \( \frac{N_1}{N_2} \) = \( \frac{32}{4} \) = 8
| 200 lbs. | |
| 50 lbs. | |
| 100 lbs. | |
| 0 lbs. |
To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.Solving for Ra, our missing value, and plugging in our variables yields:
Ra = \( \frac{R_bd_b}{d_a} \) = \( \frac{25 lbs. \times 6 ft.}{3 ft.} \) = \( \frac{150 ft⋅lb}{3 ft.} \) = 50 lbs.
Power is the rate at which:
potential energy is converted into kinetic energy |
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input force is transferred to output force |
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friction is overcome |
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work is done |
Power is the rate at which work is done, P = w/t, or work per unit time. The watt (W) is the unit for power and is equal to 1 joule (or newton-meter) per second. Horsepower (hp) is another familiar unit of power used primarily for rating internal combustion engines. 1 hp equals 746 watts.