ASVAB Mechanical Comprehension Practice Test 740783 Results

Your Results Global Average
Questions 5 5
Correct 0 3.13
Score 0% 63%

Review

1

Drag is a type of:

81% Answer Correctly

kinetic energy

work

potential energy

friction


Solution

Drag is friction that opposes movement through a fluid like liquid or air. The amount of drag depends on the shape and speed of the object with slower objects experiencing less drag than faster objects and more aerodynamic objects experiencing less drag than those with a large leading surface area.


2

Friction between two or more solid objects that are not moving relative to each other is called:

73% Answer Correctly

dynamic friction

kinetic friction

static friction

gravitational friction


Solution

Static friction is friction between two or more solid objects that are not moving relative to each other. An example is the friction that prevents a box on a sloped surface from sliding farther down the surface.


3

What's the first gear in a gear train called?

57% Answer Correctly

input gear

driver gear

idler gear

driven gear


Solution

A gear train is two or more gears linked together. Gear trains are designed to increase or reduce the speed or torque outpout of a rotating system or change the direction of its output. The first gear in the chain is called the driver and the last gear in the chain the driven gear with the gears between them called idler gears.


4

The science that deals with motion and the forces that produce motion is called which of the following?

57% Answer Correctly

aeronautics

physics

mechanics

engineering


Solution

Mechanics deals with motion and the forces that produce motion.


5 If A = 11 ft., B = 2 ft., C = 6 ft., the green box weighs 50 lbs. and the blue box weighs 65 lbs., what does the orange box have to weigh for this lever to balance?
44% Answer Correctly
280 lbs.
550 lbs.
70 lbs.
23.33 lbs.

Solution
In order for this lever to balance, the torque acting on each side of the fulrum must be equal. So, the torque produced by A must equal the torque produced by B and C. Torque is weight x distance from the fulcrum which means that the following must be true for the lever to balance:

fAdA = fBdB + fCdC

For this problem, this equation becomes:

50 lbs. x 11 ft. = 65 lbs. x 2 ft. + fC x 6 ft.

550 ft. lbs. = 130 ft. lbs. + fC x 6 ft.

fC = \( \frac{550 ft. lbs. - 130 ft. lbs.}{6 ft.} \) = \( \frac{420 ft. lbs.}{6 ft.} \) = 70 lbs.