ASVAB Mechanical Comprehension Practice Test 748857 Results

Your Results Global Average
Questions 5 5
Correct 0 2.86
Score 0% 57%

Review

1

Force of friction due to kinetic friction is __________ the force of friction due to static friction.

40% Answer Correctly

higher than

lower than

opposite

the same as


Solution

The formula for force of friction (Ff) is the same whether kinetic or static friction applies: Ff = μFN. To distinguish between kinetic and static friction, μk and μs are often used in place of μ.


2

Which of the following is not a type of simple machine?

58% Answer Correctly

screw

gear

pulley

lever


Solution

The six types of simple machines are the lever, wheel and axle, pulley, inclined plane, wedge, and screw.


3 If the radius of the axle is 7 and the radius of the wheel is 8, what is the mechanical advantage of this wheel and axle configuration?
52% Answer Correctly
1.14
-1
8
0.88

Solution

The mechanical advantage of a wheel and axle is the input radius divided by the output radius:

MA = \( \frac{r_i}{r_o} \)

In this case, the input radius (where the effort force is being applied) is 8 and the output radius (where the resistance is being applied) is 7 for a mechanical advantage of \( \frac{8}{7} \) = 1.14


4

Friction between two or more solid objects that are not moving relative to each other is called:

73% Answer Correctly

gravitational friction

static friction

kinetic friction

dynamic friction


Solution

Static friction is friction between two or more solid objects that are not moving relative to each other. An example is the friction that prevents a box on a sloped surface from sliding farther down the surface.


5 If 25 lbs. of force is applied 6 ft. from the fulcrum at the blue arrow and the green box is 2 ft. from the fulcrum, how much would the green box have to weigh to balance the lever?
62% Answer Correctly
300 lbs.
4 lbs.
37.5 lbs.
75 lbs.

Solution

To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.

Solving for Ra, our missing value, and plugging in our variables yields:

Ra = \( \frac{R_bd_b}{d_a} \) = \( \frac{25 lbs. \times 6 ft.}{2 ft.} \) = \( \frac{150 ft⋅lb}{2 ft.} \) = 75 lbs.