| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.00 |
| Score | 0% | 60% |
| 0 lbs. | |
| 1 lbs. | |
| 67.5 lbs. | |
| 16.88 lbs. |
To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.Solving for Ra, our missing value, and plugging in our variables yields:
Ra = \( \frac{R_bd_b}{d_a} \) = \( \frac{15 lbs. \times 9 ft.}{8 ft.} \) = \( \frac{135 ft⋅lb}{8 ft.} \) = 16.88 lbs.
A a seesaw / teeter-totter is an example of which of the following?
second-class lever |
|
inclined plane |
|
third-class lever |
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first-class lever |
A first-class lever is used to increase force or distance while changing the direction of the force. The lever pivots on a fulcrum and, when a force is applied to the lever at one side of the fulcrum, the other end moves in the opposite direction. The position of the fulcrum also defines the mechanical advantage of the lever. If the fulcrum is closer to the force being applied, the load can be moved a greater distance at the expense of requiring a greater input force. If the fulcrum is closer to the load, less force is required but the force must be applied over a longer distance. An example of a first-class lever is a seesaw / teeter-totter.
A wedge is most similar to what other type of simple machine?
second-class lever |
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third-class lever |
|
inclined plane |
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first-class lever |
The wedge is a moving inclined plane that is used to lift, hold, or break apart an object. A wedge converts force applied to its blunt end into force perpendicular to its inclined surface. In contrast to a stationary plane where force is applied to the object being moved, with a wedge the object is stationary and the force is being applied to the plane. Examples of a wedge include knives and chisels.
Which of the following will increase the mechanical advantage of a second-class lever?
move the object being lifted closer to the fulcrum |
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decrease the length of the lever |
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move the object being lifted farther away from the fulcrum |
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move the fulcrum between the force and the object being lifted |
A second-class lever is used to increase force on an object in the same direction as the force is applied. This lever requires a smaller force to lift a larger load but the force must be applied over a greater distance. The fulcrum is placed at one end of the lever and mechanical advantage increases as the object being lifted is moved closer to the fulcrum or the length of the lever is increased. An example of a second-class lever is a wheelbarrow.
| 270 lbs. | |
| 5 lbs. | |
| 67.5 lbs. | |
| 33.75 lbs. |
fAdA = fBdB + fCdC
For this problem, this equation becomes:
50 lbs. x 9 ft. = 60 lbs. x 3 ft. + fC x 4 ft.
450 ft. lbs. = 180 ft. lbs. + fC x 4 ft.
fC = \( \frac{450 ft. lbs. - 180 ft. lbs.}{4 ft.} \) = \( \frac{270 ft. lbs.}{4 ft.} \) = 67.5 lbs.