ASVAB Mechanical Comprehension Practice Test 794752 Results

Your Results Global Average
Questions 5 5
Correct 0 3.10
Score 0% 62%

Review

1 How much resistance could a 135 lb. effort force lift using a block and tackle pulley that has 4 ropes supporting the resistance?
81% Answer Correctly
810 lbs.
540 lbs.
534 lbs.
180 lbs.

Solution

The mechanical advantage (MA) of a block and tackle pulley is equal to the number of times the effort force changes direction. An easy way to count how many times the effort force changes direction is to count the number of ropes that support the resistance which, in this problem, is 4. With a MA of 4, a 135 lbs. effort force could lift 135 lbs. x 4 = 540 lbs. resistance.


2 If the green box weighs 20 lbs. and is 1 ft. from the fulcrum, how much force would need to be applied at the blue arrow to balance the lever if the arrow's distance from the fulcrum is 5 ft.?
62% Answer Correctly
4 lbs.
16 lbs.
12 lbs.
1 lbs.

Solution

To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.

Solving for Rb, our missing value, and plugging in our variables yields:

Rb = \( \frac{R_ad_a}{d_b} \) = \( \frac{20 lbs. \times 1 ft.}{5 ft.} \) = \( \frac{20 ft⋅lb}{5 ft.} \) = 4 lbs.


3 If 50 lbs. of force is applied 5 ft. from the fulcrum at the blue arrow and the green box is 4 ft. from the fulcrum, how much would the green box have to weigh to balance the lever?
62% Answer Correctly
125 lbs.
10 lbs.
0 lbs.
62.5 lbs.

Solution

To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.

Solving for Ra, our missing value, and plugging in our variables yields:

Ra = \( \frac{R_bd_b}{d_a} \) = \( \frac{50 lbs. \times 5 ft.}{4 ft.} \) = \( \frac{250 ft⋅lb}{4 ft.} \) = 62.5 lbs.


4

A wedge converts force applied to its blunt end into force __________ its inclined surface.

57% Answer Correctly

opposite to

parallel to

perpendicular to

along


Solution

The wedge is a moving inclined plane that is used to lift, hold, or break apart an object. A wedge converts force applied to its blunt end into force perpendicular to its inclined surface. In contrast to a stationary plane where force is applied to the object being moved, with a wedge the object is stationary and the force is being applied to the plane. Examples of a wedge include knives and chisels.


5

Which of the following is not a type of structural load?

50% Answer Correctly

live load

dead load

occupancy load

wind load


Solution

Dead load is the weight of the building and materials, live load is additional weight due to occupancy or use, snow load is the weight of accumulated snow on a structure and wind load is the force of wind pressures against structure surfaces.