ASVAB Mechanical Comprehension Practice Test 79719 Results

Your Results Global Average
Questions 5 5
Correct 0 3.07
Score 0% 61%

Review

1

The standard unit of energy is the:

73% Answer Correctly

Joule

Volt

Watt

Horsepower


Solution

The Joule (J) is the standard unit of energy and has the unit \({kg \times m^2} \over s^2\).


2

Hydraulics is the transmission of force through the use of which of the following?

73% Answer Correctly

liquids

air pressure

torque

gear systems


Solution

Hydraulics is the transmission of force through the use of liquids. Liquids are especially suited for transferring force in complex machines because they compress very little and can occupy very small spaces. Hydraulic pressure is calculated by dividing force by the area over which it is applied: P = F/A where F is force in pounds, A is area in square inches, and the resulting pressure is in pounds per square inch (psi).


3

What's the last gear in a gear train called?

38% Answer Correctly

driver gear

idler gear

driven gear

output gear


Solution

A gear train is two or more gears linked together. Gear trains are designed to increase or reduce the speed or torque outpout of a rotating system or change the direction of its output. The first gear in the chain is called the driver and the last gear in the chain the driven gear with the gears between them called idler gears.


4 If the green box weighs 55 lbs. and is 5 ft. from the fulcrum, how much weight would need to be placed at the blue arrow to balance the lever if the arrow's distance from the fulcrum is 4 ft.?
63% Answer Correctly
220 lbs.
13 lbs.
137.5 lbs.
68.75 lbs.

Solution

To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.

Solving for Rb, our missing value, and plugging in our variables yields:

Rb = \( \frac{R_ad_a}{d_b} \) = \( \frac{55 lbs. \times 5 ft.}{4 ft.} \) = \( \frac{275 ft⋅lb}{4 ft.} \) = 68.75 lbs.


5 What is the efficiency of a machine has work input of 230 ft⋅lb and work output of 115 ft⋅lb?
67% Answer Correctly
25%
0%
50%
2%

Solution
Due to friction, a machine will never be able to utilize 100% of its work input. A certain percentage of that input will be lost in overcoming friction within the machine. Effeciency is a measure of how much of a machine's work input can be turned into useful work output and is calculated by dividing work output by work input and multiplying the result by 100:
\( Efficiency = \frac{Work_{out}}{Work_{in}} \times 100 \) \( = \frac{115 ft⋅lb}{230 ft⋅lb} \times 100 \) \( = 50% \) %