| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.85 |
| Score | 0% | 57% |
Drag is a type of:
kinetic energy |
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potential energy |
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work |
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friction |
Drag is friction that opposes movement through a fluid like liquid or air. The amount of drag depends on the shape and speed of the object with slower objects experiencing less drag than faster objects and more aerodynamic objects experiencing less drag than those with a large leading surface area.
Which of the following is not a type of structural load?
dead load |
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live load |
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occupancy load |
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wind load |
Dead load is the weight of the building and materials, live load is additional weight due to occupancy or use, snow load is the weight of accumulated snow on a structure and wind load is the force of wind pressures against structure surfaces.
Which class of lever offers no mechanical advantage?
none of these, all levers offer mechanical advantage |
|
first |
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second |
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third |
A third-class lever is used to increase distance traveled by an object in the same direction as the force applied. The fulcrum is at one end of the lever, the object at the other, and the force is applied between them. This lever does not impart a mechanical advantage as the effort force must be greater than the load but does impart extra speed to the load. Examples of third-class levers are shovels and tweezers.
Which of the following represents the force a surface exerts when an object presses against it?
friction |
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counter force |
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normal force |
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mass |
Normal force (FN) represents the force a surface exerts when an object presses against it.
| 300 lbs. | |
| 9 lbs. | |
| 0 lbs. | |
| 75 lbs. |
To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.Solving for Ra, our missing value, and plugging in our variables yields:
Ra = \( \frac{R_bd_b}{d_a} \) = \( \frac{45 lbs. \times 5 ft.}{3 ft.} \) = \( \frac{225 ft⋅lb}{3 ft.} \) = 75 lbs.