ASVAB Mechanical Comprehension Practice Test 83285 Results

Your Results Global Average
Questions 5 5
Correct 0 3.33
Score 0% 67%

Review

1

What type of load doesn't create specific stress points or vary with time?

60% Answer Correctly

impact load

concentrated load

static uniformly distributed load

non-uniformly distributed load


Solution

A concentrated load acts on a relatively small area of a structure, a static uniformly distributed load doesn't create specific stress points or vary with time, a dynamic load varies with time or affects a structure that experiences a high degree of movement, an impact load is sudden and for a relatively short duration and a non-uniformly distributed load creates different stresses at different locations on a structure.


2

For any given surface, the coefficient of static friction is ___________ the coefficient of kinetic friction.

54% Answer Correctly

opposite

higher than

lower than

equal to


Solution

For any given surface, the coefficient of static friction is higher than the coefficient of kinetic friction. More force is required to initally get an object moving than is required to keep it moving. Additionally, static friction only arises in response to an attempt to move an object (overcome the normal force between it and the surface).


3 If 50 lbs. of force is applied 9 ft. from the fulcrum at the blue arrow and the green box is 7 ft. from the fulcrum, how much would the green box have to weigh to balance the lever?
62% Answer Correctly
257.14 lbs.
64.29 lbs.
0 lbs.
5 lbs.

Solution

To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.

Solving for Ra, our missing value, and plugging in our variables yields:

Ra = \( \frac{R_bd_b}{d_a} \) = \( \frac{50 lbs. \times 9 ft.}{7 ft.} \) = \( \frac{450 ft⋅lb}{7 ft.} \) = 64.29 lbs.


4 70 lbs. of effort is used by a machine to lift a 560 lbs. box. What is the mechanical advantage of the machine?
84% Answer Correctly
8
16
24
7.2

Solution

Mechanical advantage is resistance force divided by effort force:

MA = \( \frac{F_r}{F_e} \) = \( \frac{560 lbs.}{70 lbs.} \) = 8


5

The mechanical advantage of connected gears is proportional to which characteristic of the gears?

73% Answer Correctly

circumference

number of teeth

speed

diameter


Solution

The mechanical advantage (amount of change in speed or torque) of connected gears is proportional to the number of teeth each gear has. Called gear ratio, it's the ratio of the number of teeth on the larger gear to the number of teeth on the smaller gear.  For example, a gear with 12 teeth connected to a gear with 9 teeth would have a gear ratio of 4:3.