ASVAB Mechanical Comprehension Practice Test 832917 Results

Your Results Global Average
Questions 5 5
Correct 0 3.14
Score 0% 63%

Review

1

When all forces acting on a system cancel each other out, this is called:

80% Answer Correctly

stasis

potential energy

equilibrium

rest


Solution

When a system is stable or balanced (equilibrium) all forces acting on the system cancel each other out. In the case of torque, equilibrium means that the sum of the anticlockwise moments about a center of rotation equal the sum of the clockwise moments.


2 If the green box weighs 60 lbs. and 45 lbs. of force is applied 9 ft. from the fulcrum at the blue arrow, how far from the fulcrum would the green box need to be placed to balance the lever?
55% Answer Correctly
2.25 ft.
6.75 ft.
20.25 ft.
13.5 ft.

Solution

To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.

Solving for da, our missing value, and plugging in our variables yields:

da = \( \frac{R_bd_b}{R_a} \) = \( \frac{45 lbs. \times 9 ft.}{60 lbs.} \) = \( \frac{405 ft⋅lb}{60 lbs.} \) = 6.75 ft.


3 If a 45 lbs. weight is placed 3 ft. from the fulcrum at the blue arrow and the green box is 4 ft. from the fulcrum, how much would the green box have to weigh to balance the lever?
61% Answer Correctly
11.25 lbs.
8.44 lbs.
16.88 lbs.
33.75 lbs.

Solution

To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.

Solving for Ra, our missing value, and plugging in our variables yields:

Ra = \( \frac{R_bd_b}{d_a} \) = \( \frac{45 lbs. \times 3 ft.}{4 ft.} \) = \( \frac{135 ft⋅lb}{4 ft.} \) = 33.75 lbs.


4 If the green box weighs 15 lbs. and is 3 ft. from the fulcrum, how much weight would need to be placed at the blue arrow to balance the lever if the arrow's distance from the fulcrum is 8 ft.?
63% Answer Correctly
16.88 lbs.
22.5 lbs.
2.81 lbs.
5.63 lbs.

Solution

To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.

Solving for Rb, our missing value, and plugging in our variables yields:

Rb = \( \frac{R_ad_a}{d_b} \) = \( \frac{15 lbs. \times 3 ft.}{8 ft.} \) = \( \frac{45 ft⋅lb}{8 ft.} \) = 5.63 lbs.


5

Assuming force applied remains constant, which of the following will result in more work being done?

53% Answer Correctly

moving the object with more acceleration

moving the object with more speed

increasing the coefficient of friction

moving the object farther


Solution

Work is accomplished when force is applied to an object: W = Fd where F is force in newtons (N) and d is distance in meters (m). Thus, the more force that must be applied to move an object, the more work is done and the farther an object is moved by exerting force, the more work is done.