| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.66 |
| Score | 0% | 53% |
What type of load varies with time or affects a structure that experiences a high degree of movement?
impact load |
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dynamic load |
|
concentrated load |
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static load |
A concentrated load acts on a relatively small area of a structure, a static uniformly distributed load doesn't create specific stress points or vary with time, a dynamic load varies with time or affects a structure that experiences a high degree of movement, an impact load is sudden and for a relatively short duration and a non-uniformly distributed load creates different stresses at different locations on a structure.
Depending on where you apply effort and resistance, the wheel and axle can multiply:
speed or power |
|
force or speed |
|
force or distance |
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power or distance |
If you apply the resistance to the axle and the effort to the wheel, the wheel and axle will multiply force and if you apply the resistance to the wheel and the effort to the axle, it will multiply speed.
A fixed pulley is useful for which of the following?
multiplying the input force |
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changing the direction of the output force |
|
changing the direction of the input force |
|
multiplying the input distance |
A fixed pulley is used to change the direction of a force and does not multiply the force applied. As such, it has a mechanical advantage of one. The benefit of a fixed pulley is that it can allow the force to be applied at a more convenient angle, for example, pulling downward or horizontally to lift an object instead of upward.
| 0.42 lbs. | |
| 5 lbs. | |
| 1.67 lbs. | |
| 6.67 lbs. |
To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.Solving for Ra, our missing value, and plugging in our variables yields:
Ra = \( \frac{R_bd_b}{d_a} \) = \( \frac{10 lbs. \times 1 ft.}{6 ft.} \) = \( \frac{10 ft⋅lb}{6 ft.} \) = 1.67 lbs.
| 17 \( \frac{ft⋅lb}{s} \) | |
| 7012.5 \( \frac{ft⋅lb}{s} \) | |
| 1168.8 \( \frac{ft⋅lb}{s} \) | |
| 2337.5 \( \frac{ft⋅lb}{s} \) |