ASVAB Mechanical Comprehension Practice Test 871808 Results

Your Results Global Average
Questions 5 5
Correct 0 3.54
Score 0% 71%

Review

1

What type of load acts on a relatively small area of a structure?

74% Answer Correctly

dynamic load

non-uniformly distributed load

impact load

concentrated load


Solution

A concentrated load acts on a relatively small area of a structure, a static uniformly distributed load doesn't create specific stress points or vary with time, a dynamic load varies with time or affects a structure that experiences a high degree of movement, an impact load is sudden and for a relatively short duration and a non-uniformly distributed load creates different stresses at different locations on a structure.


2 50 lbs. of effort is used by a machine to lift a 350 lbs. box. What is the mechanical advantage of the machine?
84% Answer Correctly
2
7
7.7
6.3

Solution

Mechanical advantage is resistance force divided by effort force:

MA = \( \frac{F_r}{F_e} \) = \( \frac{350 lbs.}{50 lbs.} \) = 7


3

Tension is a force that does which of the following?

76% Answer Correctly

stretches an object

compacts an object

heats up an object

slows an object


Solution

Tension is a force that stretches or elongates something. When a cable or rope is used to pull an object, for example, it stretches internally as it accepts the weight that it's moving. Although tension is often treated as applying equally to all parts of a material, it's greater at the places where the material is under the most stress.


4 If the green box weighs 45 lbs. and is 9 ft. from the fulcrum, how far from the fulcrum would a 25 lbs. weight need to be placed to balance the lever?
61% Answer Correctly
5.4 ft.
4.05 ft.
5 ft.
16.2 ft.

Solution

To balance this lever the torques on each side of the fulcrum must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the left side of the fulcrum and b the right, R is resistance (weight) and d is the distance from the fulcrum.

Solving for db, our missing value, and plugging in our variables yields:

db = \( \frac{R_ad_a}{R_b} \) = \( \frac{45 lbs. \times 9 ft.}{25 lbs.} \) = \( \frac{405 ft⋅lb}{25 lbs.} \) = 16.2 ft.


5 If the green box weighs 40 lbs. and is 3 ft. from the fulcrum, how far from the fulcrum would a 5 lbs. force need to be applied to balance the lever?
58% Answer Correctly
24 ft.
72 ft.
6 ft.
13 ft.

Solution

To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.

Solving for db, our missing value, and plugging in our variables yields:

db = \( \frac{R_ad_a}{R_b} \) = \( \frac{40 lbs. \times 3 ft.}{5 lbs.} \) = \( \frac{120 ft⋅lb}{5 lbs.} \) = 24 ft.