| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.22 |
| Score | 0% | 64% |
If the handles of a wheelbarrow are 3 ft. from the wheel axle, what force must you exert to lift the handles if it's carrying a 270 lb. load concentrated at a point 0.5 ft. from the axle?
45 lbs |
|
0.83 lbs |
|
810 lbs |
|
90 lbs |
This problem describes a second-class lever and, for a second class lever, the effort force multiplied by the effort distance equals the resistance force multipied by the resistance distance: Fede = Frdr. Plugging in the variables from this problem yields:
Fe x 3 ft. = 270 lbs x 0.5 ft
Fe = 135 ft-lb. / 3 ft
Fe = 45 lbs
| 8.57 ft. | |
| 4.29 ft. | |
| 2.14 ft. | |
| 7 ft. |
fAdA = fBdB
For this problem, the equation becomes:
15 lbs. x 5 ft. = 35 lbs. x dB
dB = \( \frac{15 \times 5 ft⋅lb}{35 lbs.} \) = \( \frac{75 ft⋅lb}{35 lbs.} \) = 2.14 ft.
An inclined plane increases ___________ to reduce ____________.
force, distance |
|
force, power |
|
distance, power |
|
distance, force |
An inclined plane is a simple machine that reduces the force needed to raise an object to a certain height. Work equals force x distance and, by increasing the distance that the object travels, an inclined plane reduces the force necessary to raise it to a particular height. In this case, the mechanical advantage is to make the task easier. An example of an inclined plane is a ramp.
| 0 ft⋅lb | |
| 35 ft⋅lb | |
| 344 ft⋅lb | |
| 51 ft⋅lb |
| 55 ft. | |
| 440 ft. | |
| 2 ft. | |
| 0 ft. |
Win = Wout
Feffort x deffort = Fresistance x dresistance
In this problem, the effort work is 440 ft⋅lb and the resistance force is 220 lbs. and we need to calculate the resistance distance:
Win = Fresistance x dresistance
440 ft⋅lb = 220 lbs. x dresistance
dresistance = \( \frac{440ft⋅lb}{220 lbs.} \) = 2 ft.