| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.01 |
| Score | 0% | 60% |
The measure of how much of the power put into a machine is turned into movement or force is called:
mechanical advantage |
|
force multiplication |
|
efficiency |
|
power |
The efficiency of a machine describes how much of the power put into the machine is turned into movement or force. A 100% efficient machine would turn all of the input power into output movement or force. However, no machine is 100% efficient due to friction, heat, wear and other imperfections that consume input power without delivering any output.
| 7 | |
| -5 | |
| 0.58 | |
| 1.71 |
The mechanical advantage of a wheel and axle is the input radius divided by the output radius:
MA = \( \frac{r_i}{r_o} \)
In this case, the input radius (where the effort force is being applied) is 12 and the output radius (where the resistance is being applied) is 7 for a mechanical advantage of \( \frac{12}{7} \) = 1.71
Which of the following is not a modulus of elasticity?
shear modulus |
|
bulk modulus |
|
stretch modulus |
|
stress modulus |
The modulus of elasticity measures how much a material or structure will deflect under stress. Stretch modulus is longitudinal stretch (like stretching raw bread dough), shear modulus is longitudinal deflection (like the horizontal displacement of a stack of magzines when a heavy object is placed upon them), and bulk modulus is compression of volume (like the compression of a loaf of bread under a heavy can at the bottom of a grocery bag).
| 30.56 lbs. | |
| 0 lbs. | |
| 91.67 lbs. | |
| 7.64 lbs. |
To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:
Rada = Rbdb
where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.Solving for Rb, our missing value, and plugging in our variables yields:
Rb = \( \frac{R_ad_a}{d_b} \) = \( \frac{55 lbs. \times 5 ft.}{9 ft.} \) = \( \frac{275 ft⋅lb}{9 ft.} \) = 30.56 lbs.
| 2 | |
| 8 | |
| 16 | |
| 7.2 |
Mechanical advantage is resistance force divided by effort force:
MA = \( \frac{F_r}{F_e} \) = \( \frac{240 lbs.}{30 lbs.} \) = 8